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igomit [66]
3 years ago
12

What is the volume of a sphere with a radius of 9 inches

Mathematics
2 answers:
Effectus [21]3 years ago
7 0
Given the formula 
V=\frac{4}{3}πR³
so V=\frac{4}{3}π9³=972π
Sveta_85 [38]3 years ago
7 0

Answer: 972π in.³

Step-by-step explanation: To find the volume of a sphere, start with the formula for the volume of a sphere.

Volume = \frac{4}{3} \pi r^{3}

Notice that our sphere has a radius of 9 inches, so we can plug a 9 in for the radius in our formula.

Volume = (\frac{4}{3}) (\pi)(9in.)^{3}

Start by simplifying the exponent. (9 in.)³ is equal to 9 inches × 9 inches × 9 inches or 729 in.³.

Volume = (\frac{4}{3})(729 in^{3})(\pi)

Notice that we can cross cancel the 3 in 4/3 and 729 to 1 and 243.

Volume = (4) (243 in³) (π)

Volume = 972π in.³

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3 years ago
The point (21, 32) is on a line with slope 1.5
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Ok so for this question, you have to draw a graph to help. I'm doing the numbers by 2. You plot the points (21,32) on the graph then after that plot the points by the slope. What I'm trying to say by that is: 1.5 as a fraction is 3/2. so you count from that point by going 3 numbers up (or squares if on a graph if it makes more sense) then count 2 squares to the right and you continue doing that after every point you make (if there's no space to go up the graph the n you can go down by just counting 3 down then counting 2 to the LEFT)

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7 0
3 years ago
Read 2 more answers
Can you form a triangle with the following segments 6,5,3?
LenaWriter [7]

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yes

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Hope this helps. Have a nice day. May it be filled with joy and happiness. Please, stay safe and wash your hands/wear a mask when in public. Happy Holidays.

4 0
2 years ago
Salaries of 40 college graduates who took a statistics course in college have a mean of $62, 200. Assuming a standard deviation
ololo11 [35]

Answer:

Step-by-step explanation:

We want to determine a 90% confidence interval for the mean salaries of college graduates

Number of sample, n = 40

Mean, u = $62, 200

Standard deviation, s = $11,766

For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean +/- z ×standard deviation/√n

It becomes

62200 +/- 1.645 × 11766/√40

= 62200 +/- 1.645 × 1860.4

= 62200 +/- 3060.358

The lower end of the confidence interval is 62200 - 3060.358 =59139.642

The upper end of the confidence interval is 62200 + 3060.358 =65260.358

Therefore, with 90% confidence interval, the mean mean salaries of college graduates is between $59139.642 and $65260.358

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