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natka813 [3]
3 years ago
7

How would you make an extract of a food to test for reducing sugar​

Biology
1 answer:
alexdok [17]3 years ago
6 0
To test for the presence of reducing sugars, a food sample is dissolved in boiling water. Next, a small amount of Benedict's reagent is added and the solution begins to cool. During the next four to 10 minutes, the solution should begin to change colors. If the color changes to blue, then no glucose is present. If a high amount of glucose is present, then the color change will progress to green, yellow, orange, red and then a dark red or brown.
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Which of the following are possible results of mutated genes?
Nimfa-mama [501]

Answer:

harmful effect and no effect

Explanation:

No effect: most mutated genes destroy themselves before it gets to far

Harmful effect: an example of harmful effects would be down-syndrome (where you have 3 21-chromosomes and you are only supposed to have 2)

6 0
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Suppose the human trait for hair type is controlled by a simple dominant and recessive relationship at one locus. Curly hair, C,
myrzilka [38]

Answer:

A) The frequency of the dominant allele, C = 0.4376

B) frequency of the heterozygous genotype, Cc = 0.2461

Explanation:

Given -

Curly hair, C, is the dominant allele, and straight hair, c, is the recessive allele

Number of students with curly hair is 37

Thus frequency of genotype "CC"

= q^{2} = \frac{37}{117} \\= 0.3162

Thus, frequency of allele "q"

= \sqrt{0.3162} \\= 0.5623

As per Hardy Weinberg's first  equation-

p+q=1

Substituting the value of q, we get -

p+0.5623=1\\p= 0.4376

As per Hardy Weinberg's second equation -

p^2+q^2+2pq=1\\

Substituting the values of "p" and "q" we get -

0.4376^{2} + 0.3162+2pq = 1\\2pq = 0.2461\\

Hence,

A) The frequency of the dominant allele, C = 0.4376

B) frequency of the heterozygous genotype, Cc = 0.2461

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