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Usimov [2.4K]
4 years ago
7

john set a record when he caught a salmon that weighed 97 1/2pounds. james caught a salmon that weighed 74 7/16pounds. How much

less than the record was this?
Mathematics
1 answer:
ZanzabumX [31]4 years ago
5 0

Answer:

23.0625 or 23 13/200

Step-by-step explanation:

97 1/2 - 74 7/16 = 23.065 or 23 13/200

Fun fact: The heaviest salmon caught is actually 97 pounds!

If you found this helpful, please give me brainliest. Thanks!

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Zanzabum
Collect likes terms firstly
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Divide everything by two to get the value of z
So your answer is -12.5
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MissTica

Sherri bought a beach towel that normally cost $44 but was on sale for half price she also bought a beach hat that was on sale for $12 off before tax her total cost was $38 what was the regular price of the beach at

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What is the slope of the line? (Write your answer as a reduced fraction)
hoa [83]

Answer:

m=-1/4

Step-by-step explanation:

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3 years ago
Find all two digit positive integers in which the difference between the integer and the product of its two digits is 12
mojhsa [17]
Let ab be a 2 digit number, then ab=10a+b, where a and b are digits, a≠0.

"the difference between the integer and the product of its two digits is 12"

10a+b - (a*b)=12

10a+b-ab=12

factorize b:

10a+b(1-a)=12

subtract 10 from both sides, to produce a factor (1-a) or (a-1) and then factorize:

10a-10+b(1-a)=2

10(a-1)+b(1-a)=2

(a-1)(10-b)=2

(a-1)(10-b) can be (1,2), (2, 1), (-1, -2), (-2, -1)

if a-1=1 and 10-b=2, then a=2, b=8
if a-1=2, and 10-b=1, then a=3, b=9
if a-1=-1, then a=0, which is not possible
if a-1=-2, then a=-1, which is not possible


so the solutions (a, b) are (2, 8) and (3, 9)


Then the integers are 28, 39


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4 0
3 years ago
The original value of a car is $24,000. It depreciates 15% annually. What is its value in 4 years? $
ValentinkaMS [17]

Answer:

Future Value = $ 12528.15

Step-by-step explanation:

The depreciation is applied to the car annually. The value of the car after depreciation in "n" no. of years can be given by the following formula:

Future\ Value = (Present\ Value)(1-depreciation\ rate)^n\\

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Future Value = ?

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n = no. of years = 4

Therefore,

Future\ Value = (\$ 24000)(1-0.15)^4

<u>Future Value = $ 12528.15</u>

8 0
3 years ago
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