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Ghella [55]
3 years ago
7

Shelby owns a sporting goods store. She buys knowre tennis rackets at a

Mathematics
1 answer:
Helga [31]3 years ago
5 0

Answer:

$50

Step-by-step explanation:

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The total profit P of manufacturing x hundred DVD's is given by the equation below.
hichkok12 [17]

Answer:

x = -7.5

Step-by-step explanation:

P = 600 + 1,500x − 100x^2

P = − 100x^2 + 1,500x + 600

x = -b/2a

1500/ (2 x -100)

x = -7.5

7 0
3 years ago
After a car is purchased, the value of a new car decreases $4000 each year. After 3 years, the car is worth $18000.
Over [174]
Original - 4000x 

<span>so, after 3 years we have: </span>

<span>Original - 12000 = 18000 </span>

<span>=> Original = $30,000 </span>
6 0
3 years ago
What is 77 divided by 10
N76 [4]

Answer:

7.7

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
34576637 + 2373773883. l
Zigmanuir [339]

The answer to your question is: 2,408,350,520.

Give brainliest please and i hope this helps alot. :D

7 0
4 years ago
Read 2 more answers
The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.
inessss [21]

The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.

That is,

Consider X be the length of the pregnancy

Mean and standard deviation of the length of the pregnancy.

Mean \mu =266\\

Standard deviation \sigma =15

For part (a) , to find the probability of a pregnancy lasting 308 days or longer:

That is, to find P(X\geq 308)

Using normal distribution,

z=\frac{X-\mu}{\sigma}

z=\frac{308-266}{15}

=\frac{42}{15}

Thus z=2.8

So P\left (X\geq 308  \right )=1-P(X

=1-P(z

=1-Table\:  value\:  of\:  2.8

=1-0.99744

=0.00256

Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.

This the answer for part(a): 0.00256

For part(b), to find the length that separates premature babies from those who are not premature.

Given that the length of pregnancy is in the lowest 3​%.

The z-value for the lowest of 3% is -1.8808

Then X=\frac{X-\mu}{\sigma}\Rightarrow X=z*\sigma+\mu

This implies X=-1.8808*15+266=237.788

Thus the babies who are born on or before 238 days are considered to be premature.

5 0
3 years ago
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