Answer:
x = -7.5
Step-by-step explanation:
P = 600 + 1,500x − 100x^2
P = − 100x^2 + 1,500x + 600
x = -b/2a
1500/ (2 x -100)
x = -7.5
Original - 4000x
<span>so, after 3 years we have: </span>
<span>Original - 12000 = 18000 </span>
<span>=> Original = $30,000 </span>
Answer:
7.7
Step-by-step explanation:
The answer to your question is: 2,408,350,520.
Give brainliest please and i hope this helps alot. :D
The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.
That is,
Consider X be the length of the pregnancy
Mean and standard deviation of the length of the pregnancy.
Mean 
Standard deviation \sigma =15
For part (a) , to find the probability of a pregnancy lasting 308 days or longer:
That is, to find 
Using normal distribution,



Thus 
So 




Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.
This the answer for part(a): 0.00256
For part(b), to find the length that separates premature babies from those who are not premature.
Given that the length of pregnancy is in the lowest 3%.
The z-value for the lowest of 3% is -1.8808
Then 
This implies 
Thus the babies who are born on or before 238 days are considered to be premature.