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natta225 [31]
3 years ago
14

Need help on this question don’t know what to do

Mathematics
1 answer:
irga5000 [103]3 years ago
5 0
So first thing ya gotta do is find the area of the circular plates, which the equation is A= \pi r^2 .

To get the radius, just divide the diameter, 30, by half. So in this case the radius would be 15.

Now that ya know that 15 is the radius, you can plug it into the equation.

A= \pi 15^2

A=225 \pi (I would advise you don't round anything until the end to get more accurate answers.)

So now that you know the area of the plate, you're gonna just multiply the area by 1/3 for lasagna and 2/3 for the salad.

225 \pi ( \frac{1}{3} )=235.6

225 \pi ( \frac{2}{3} )=471.2

(also make sure to use cm^2 units!)
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If the length of a diagonal of a square is a, what is the length of its side?
balandron [24]

problem decoded dude

thank and follow me :)

3 0
3 years ago
Help needed with this!!!
gulaghasi [49]
2,7) is the answer to this question
5 0
3 years ago
PLESE HELPPP!!!!!!!!!!!!!!!!
zzz [600]

Answer:

B. \frac{6}{2x^{2}  - 5x}

Step-by-step explanation:

The product of the ratioal expressions given above can be found as follows:

= \frac{2}{x} * \frac{3}{2x - 5}

Multiply the denominators together, and the numerators together, separately to get a single expression

\frac{2(3)}{x(2x - 5)}

= \frac{6}{x(2x) - x(5)}

= \frac{6}{2x^{2}  - 5x}

The product of the expression \ = \frac{2}{x}*\frac{3}{2x - 5} = \frac{6}{2x^{2}  - 5x}

The answer is B.

8 0
3 years ago
Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow
prisoha [69]

Answer:

The answers is " Option B".

Step-by-step explanation:

CI=\hat{Y}\pm t_{Critical}\times S_{e}

Where,

\hat{Y}= predicted value of lead content when traffic flow is 15.

\to df=n-1=8-1=7

 95\% \ CI\  is\  (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\

     =\frac{1059.8}{2}\\\\=529.9

Calculating thet-critical valuet_{ \{\frac{\alpha}{2},\ df \}}=-2.365

The lower predicted value =529.9-2.365(Se)

463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076

When 99\% of CI use as the expected lead content: \to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)

8 0
3 years ago
Solve the simultaneous equations<br> x + 6y = 20<br> x + 3y = 14<br> x =<br> Y=
xxTIMURxx [149]

Answer:

x = 8, y = 2

Step-by-step explanation:

Multiply the second equation by -2:

x + 6y = 20

-2x - 6y = -28

Add the equations and simplify:

-x = -8

x = 8

Plug x = 8 back into the first equation and solve for y:

8 + 6y = 20

6y = 12

y = 2

6 0
3 years ago
Read 2 more answers
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