The answer is (5,-2) because when you plug it into the first problem you would get 0 which is greater than or equal to -2 and for the second you would get -9 which is less than or equal to -2
10 kids total
picking Truman would be 1 out of 10 or 1/10
then there would be 9 kids left so picking Ryan would be 1 out of 9 or 1/9
the probability of picking both would be 1/10 * 1/9 = 1/90
Answer:
Below in bold
Step-by-step explanation:
The sequence is:
3, x, y, 18
If this is an A P then
x - 3 = y - x
2x - y = 3 (A) and
y - x = 18 - y
2y - x = 18 (B)
Multiply (A) by 2:
4x - 2y = 6 (C)
Adding B and C:
3x = 24
x = 8.
and
2y - 8 = 18
2y = 26
y = 13.
So x = 8 and y = 13.
b) ar + ar^2 = 6ar^3 where a = first term and r = common ratio
Divide by a:
r + r^2 = 6r^3
6r^3 - r^2 - r = 0
r(6r^2 - r - 1) = 0
r(3r + 1)(2r - 1) = 0
So the 2 possible values of r
= -1/3 and 1/2.
i) The common ratio is positive so it must be 1/2.
Second term ar = 8
1/2 a = 8
a = 16.
So the first 6 terms are:
16, 8, 4, 2, 1, 1/2.
The first step is to square root both sides to get the exponent out. that actually is the only step :)
