Sorry I can’t answer this right now but I’ll will answer later
Answer:
y=-½x + 1
Step-by-step explanation:
1.) a perpendicular lines uses the opposite inverse of a line so the slope becomes -½x
2.) make an equation that looks as so:
y=-½x+b
the y intercept is unknown so it must be a variable.
3.) substitute the points you are given into the equation:
3=-½(4)+b
4.) solve for b
3=2+b
-2|-2
1=b
4.) place b into the equation
y=-½x + 1
Answer:
(-2,-110)
Step-by-step explanation:
First solve for x
20x−70=70x+30
x= -2
Now substitute x for -2
y=20x−70
y=20(-2)-70
y = -110
Answer:
the answer would be B) no solution
Step-by-step explanation:
The two equations are parrael and that makes it have no solution.
Hope this helps. just let me know if you have any questions about my answer.
B. First off , standard form of a 2nd degree equation is Ax^2 + Bx + C. So look at the coefficient of Ax^2 which is -2.
If positive, the parabola opens up and has a minimum.
If negative, the parabola opens down and has a maximum.
A. To find the vertex (in this case maximum),
Graph the equation -OR—
make a table. — OR—
Find the zeroes and find the middle x-value
-2x^2 - 4x + 6
-2(x^2 +2x - 3 = 0
-2 (x - 1) ( x + 3)=0
x - 1 = 0. x + 3 = 0
x = 1. x = -3. So halfway would be at (-1, __).
Sub in -1 into original equation -2x^2 -4x + 6 … -2(-1)^2 -4(-1) + 6 = -2 +4 +6 = 8
So the vertex is (-1,8)
