Y = x^2 + 2x - 1 = x^2 + 2x + 1 - 1 - 1 = (x + 1)^2 - 2
The vertex of a parabola given by y = a(x - h)^2 + k is (h, k).
Therefore, the vertex of y = (x + 1)^2 - 2 is (-1, -2)
Y=4x+2 that my equation now graph it
Answer:
8 and 6
Step-by-step explanation:
If you use x for the first number, and y for the second, you get equations of 3x+5y=54 and x-2=y.
You can substitute the second equation into the first one to solve it. This gives 3x+5(x-2)=54.
The brackets can be expanded to 3x+5x-10=54. Collecting like terms makes it 8x-10=54.
Next, we add 10 to both sides. This gives 8x=64.
From there, we isolate the x by dividing both sides by 8, giving x=8.
To work out the second number, we can sub 8 for x in either equation (I'm using the second one as it's simpler).
This comes to y=8-2, therefore y=6.
**This content is simultaneous equations, which you may wish to revise. I'm always happy to help!
Answer:Each side of x would be 7 and each side of y would be 4.
Step-by-step explanation:
Use the distance formula.
Points S and W.



~3.6
Points S and T




~3.6
Points T and U




~3.1
Points U and V



~4
Points V and W




~3.3
Add all these together.
3.3 + 3.1 + 4 + 3.1 + 3.6
≈17