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2 years ago

Someone please help me

Mathematics

1 answer:

Nadya [2.5K]2 years ago

7 0

Answer:

Step-by-step explanation:

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vladimir2022 [97]

The answer is on the photo below, I hope I helped! Hope you do well!!!

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2 years ago

What is 0.58 as a fraction

zvonat [6]

0.58
= 58/100
= 29/50

7 0

3 years ago

Read 2 more answers

The experimental probability that Pedro will hit a hole in one at the golf course is 2/5. If Pedro goes golfing 40 times in a ye

Sati [7]

I'm pretty sure you would need to multiply 2/5 by 40.

So, if you multiply 2/5 by 40, you need to turn 40 into a fraction with 1 being the denominator.

2/5 x 40/1 = 80/5

Since the product is an improper fraction, you would simplify it to a whole number.

80/5 = 16.

He can expect to hit it 16 times to get a hole in one.

I hope I am right and have a great day.

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3 years ago

Read 2 more answers

What is the value of a in the equation? 22= a/11

OLga [1]

Answer:

Step-by-step explanation:

If you divide 33 by 11 it’ll be 3 so we can cross B off, and A too because it’s not a double digit

So that leaves us with C & D.

If we divided 222 and 11 it would leave us with 10 which doesn’t match 11, so that leaves us with D

(Sorry if I didn’t’t explain right )

6 0

2 years ago

Read 2 more answers

The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

$AV = \frac{y(t2) - y(t1)}{t2 - t1}$

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

$AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6$

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii) t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

$AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8$

So the average speed is -128.9 ft/s

iii) t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

$AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16$

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0

2 years ago