To build the table you just have to give values to t and then calculate the corresponding c a per the model.
If the model is c = 5.5 t this is the table
t c
5.5 t
0 5.5(0) = 0
1 5.5(1) = 5.5
2 5.5(2) = 11.0
3 5.5(3) = 16.5
4 5.5(4) = 22.0
5 5.5(5) = 27.5
The viables solutions are all where t is equal or greater than 0. You can even use decimal values for t. You cannot use negative values for t.
1st equation—x, substitute y:
<span>3x + 2(x + 3) = 16 </span>
<span>3x + 2x + 6 = 16 </span>
<span>5x = 10 </span>
<span>x = 2 </span>
<span>y in the above equation: </span>
<span>= 2 + 3 </span>
<span>= 5 </span>
<span>Answer: x = 2, y = 5</span>
Answer:
$ (C/t ) × 5
= $ 5C/t
.....................................
Answer:
HI SORRY IM, SPEAK SPANISH... FROMN COLOMBIA
Step-by-step explanation:
HOLI MK NO SE HABLAR INGLES CHAU
x squared = 9 NOT x
x = square roots of 9 which is +3 or -3.