For the answer to the question above, since the triangle is isosceles, the two legs have equal length. The coordinates of two vertices are given
P(3,3)
Q(3,1)
Assuming that PQ and QR are the legs of equal length, the distance between Q and R must be the same as the distance between P and Q
d = √[(3-3)² + (3-1)²
d = 2
Therefore, the coordinates of P is
(5,1)
Answer:(15, 100)
Step-by-step explanation:
first find the coordinates of the point above (3, 20)
you just look at the x axis and where the point is in this case x would be 6 and then you find y which would be 40
so the coordinate would be (6, 40)
now subtract (6, 40) by (3, 20)
6-3= 3
40- 20= 20
you get the first coordnites which is what you add (12,80) to
12 +3= 15
80+ 20= 100
you get the coordinates (15, 100)
The answer is 4. You take 2 and divide it by 0.5.
