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Stolb23 [73]
3 years ago
6

Carina is borrowing $27,000 to buy a new car. If she borrows the money at 4.15% interest compounded annually for 5 years, how mu

ch interest will she pay on her car loan?
$33,087.21
$6,087.21
$1,120.50
$5,602.50
Mathematics
2 answers:
bixtya [17]3 years ago
8 0
She will have to pay $6,087.21 in interest
Dafna11 [192]3 years ago
4 0

Answer:

NO, the these three border pieces will not make a right triangle

Step-by-step explanation:

Use the compound amount formula A = P(1 + r)^t:

Here A = ($27,000)(1 + 0.0415)^5

         A = ($27,000)(1.0415)^5 = $33,087.21

Subtracting the principal amount, $27,000, leaves the compound interest amount:  $33,087.21 - $27,000 = $6087.21

She will pay $6,087.21 interest on this loan.

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we have

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therefore

the answer is

0.0625\frac{gal}{min}

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What is the solution to the system of equations below?
Andre45 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equations

y=-6x-10

y=-3x-21

solving the system of the equations

Arrange the equation variables for elimination

\begin{bmatrix}y+6x=-10\\ y+3x=-21\end{bmatrix}

y+3x=-21

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\underline{y+6x=-10}

-3x=-11

\begin{bmatrix}y+6x=-10\\ -3x=-11\end{bmatrix}

solve

-3x=-11

Divide both sides by -3

\frac{-3x}{-3}=\frac{-11}{-3}

x=\frac{11}{3}

\mathrm{For\:}y+6x=-10\mathrm{\:plug\:in\:}x=\frac{11}{3}

y+6\cdot \frac{11}{3}=-10

y+6\cdot \frac{11}{3}=-10

y=-32

Therefore, the solutions to the system of the equations are:

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But, it seems none of the options is true.

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The point (-2, -1) satisfies which of the following inequalities?
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5 0
3 years ago
Help I need it now!!<br> T14= 46, and t20= 100, find t3, t7, and tn
Vinil7 [7]

Answer:

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Step-by-step explanation:

Arithmetic sequence:

       \sf \boxed{t_n=a+(n-1)d}

Here a is the first term and d is the common difference.

      t_{14}= 6    ⇒  \sf a + 13 d = 46  ------------(I)

     \sf t_{20} = 100 ⇒   a + 19d = 100 ---------(II)

Subtract equation (I) from (II)

(I1)    a + 19d = 100

(II)    a + 13d   =  46

      <u>-    -            -</u>

               6d = 54

                d = 54 ÷ 6

                 \sf \boxed{d = 9}

Substitute d = 9 in equation(I) and find 'a',

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\sf t_3 = -71 + 2*9

   = -71 + 18

   = -53

          \sf t_7 = -71 + 6*9

              = -71 + 54

              = -17

\sf t_n= -71 + (n-1)*9

    = -71 + 9*n - 1 *9

    = -71 + 9n - 9

    = -71 - 9 + 9n

     = - 80 + 9n

   

   

5 0
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