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stiv31 [10]
2 years ago
12

I WILL MARK BRAINLIEST!!! 45 POINTS!!!! Solve using substitution y= -8x-6 y= -3x +4

Mathematics
1 answer:
Nuetrik [128]2 years ago
3 0

Given :

y= -8x-6

y= -3x +4

By solving it, we get,

-8x-6 = -3x+4

=  > x =  - 2

Substituting the value of "x" in second given equation,

y =  - 3x + 4

=  > y =  - 3 \times ( - 2) + 4

By solving it, we get,

y = 10

Hence, the values are :-

x =  - 2 \\ y = 10

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Please help with #6 need it very soon
gregori [183]

Answer:

If this is a proof then here is the answer.

Angle ABD is Congruent to Angle CBD = Given

Angle BDA is Congruent to Angle BDC = Given

Angle ABD is Congruent to Angle CBD = Definition of Angle Bisector

Line Segment BD is Congruent to Line Segment BD = Reflexive Property

Line Segment AB is Congruent to Linge Segment CB = Angle-Side-Angle or ASA

Step-by-step explanation:

Lucky for you, I just learned this also ;)


Since you are given your first two directions, put them down as GIVEN in the proof.

Next, Since ABD and CBD are congruent angles, you can assume that it is an angle bisector since angle bisectors always bisect equally.

Then, (This one is obvious), since Line Segment BD shares a side with itself, it is equal by the Reflexive Property (EX: AB is congruent to AB).

Finally, Since there is two angles with a congruent side in the middle, you can confirm that it is equal by Angle-Side-Angle.

Hope this helped!


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All of the following expressions are equivalent except _____.
Zielflug [23.3K]
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Please solve for x z=m+x
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Answer:

x = z - m

Step-by-step explanation:

<u>Solving for x with steps:</u>

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What is the distance between -2 and 5
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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
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