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shepuryov [24]
3 years ago
15

Find each unit price to decide which is the best buy

Mathematics
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer:

do you have more info so I can help

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Solv this for T<br><br>1/5t + 2- ( ) = 17- ( ) 1/5t = ( ) × 1/5t= ( ) t =​
Olenka [21]

Answer:

t = 5?

Step-by-step explanation:

3 0
3 years ago
Iiiiiiiiytffhjhffjdjhdhdhdhdhhdhdd
SVEN [57.7K]

Answer:

x = 30

Step-by-step explanation:

The sum of the 3 interior angles of a triangle = 180°, hence

x + x + 10 + 3x + 20 = 180

5x + 30 = 180 ( subtract 30 from both sides )

5x = 150 ( divide both sides by 5 )

x = 30

8 0
3 years ago
A baseball team’s roster consists of 25 players with 13 position players and the rest being pitchers. The team’s batting order f
Dvinal [7]

Answer: C is not correct i just took the test and it was wrong.



Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
PLEASE HELP..... I WILL GIVE BRAINLIEST!!
Yakvenalex [24]
For the first part:

Every shirt she grabs, will cost her dollars, so if she grabs 3 shirts, then the cost of the shirts is:

12+12+12=3(12)

With the same rationale, if she grabs 2 pairs of jeans, the cost of the jeans is:

19+19=2(19)

So, her total is:

3(12)+2(19)

If you subtract 3 from the total, then the expression is:

3(12)+2(19)-3=36+38-3=71

For the second part:

If she's paying 3 less for each shirt, then the cost of 3 shirts will become:

(12-3)+(12-3)+(12-3)=3(12-3)

In the same fashion, for the two jeans:

(19-3)+(19-3)=2(19-3)

So the expression for the total cost is:

3(12-3)+2(19-3)=36-9+38-6=59

For number three:

The amounts are different because the cost of the total purchase is different than the cost of each element that makes up the total purchase.

For number four:

If you're the owner, you want to give the smallest amount of discount (the one in part 1/a).

So you could clarify by saying there's 3 dollars of the TOTAL purchase's cost.
6 0
4 years ago
X2 - 6x + 12 and y = 2x - 4, algebraically are
olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x^2 - 6x + 12 = 2x - 4

Make the right side of equation 0

x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0

<em><u>Solve by quadratic equation</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4

<em><u>Substitute x = 4 in eqn 2</u></em>

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0
3 years ago
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