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2 years ago

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HELP THIS IS IMPORTANT!!! The range of the following relation R {(3.-5), (1, 2), (-1,-4),(-1, 2)} is (1 point) Oa ng 1-1.1.3) Ob

{-5. -4, 2} oc {-4. - 5. 2. 2)

1 answer:

garri49 [273]2 years ago

4 0

Answer:

The range is -5,2,-4,

Step-by-step explanation:

hope that helps

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Gala2k [10]

Answer:

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Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) , then the midpoint is

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Here (x₁, y₁ ) = A (4, 6 ) and (x₂, y₂ ) = B (- 8, 2 )

midpoint = ( $\frac{4-8}{2}$ , $\frac{6+2}{2}$ ) = ( $\frac{-4}{2}$ , $\frac{8}{2}$ ) = (- 2, 4 )

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Answer:

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Step-by-step explanation:

From Algebra, we remember that quadratic functions of the form $a\cdot x^{2}+b\cdot x + c$ has solutions of the form:

$x = \frac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}$ , where both are complex if and only if $\sqrt{b^{2}-4\cdot a \cdot c}< 0$ .

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