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Katen [24]
3 years ago
12

The table shows the height, in centimeters, that a weight bouncing from a spring would achieve if there were no friction, for a

given number of seconds. Time (s) Height (cm) 0 −25 1.5 0 3 25 4.5 0 6 −25 7.5 0 9 25 10.5 0 12 −25 From its resting position, how long does it take the weight to bounce one direction, then the other, and then back to its resting position? Enter your answer in the box. s
Mathematics
1 answer:
Paha777 [63]3 years ago
4 0
Hello! For ease of calculations, we can identify the time it took for the weight to bounce back to the other direction, then the other, and then back to its original position by looking at the time it took for the weight to change from 0 to 25 to 0 to -25 then back to 0. This is one whole cycle of the weight.

By the time the weight first reached zero, 1.5 seconds has passed. By the third time it got to zero again, 7.5 seconds has passed. Therefore, one whole cycle of the weight is 7.5-1.5 = 6.0 seconds.

ANSWER: One whole cycle of the weight took 6 seconds.
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Demand for your tie-dyed T-shirts is given by the formula q = 510 − 90p0.5 where q is the number of T-shirts you can sell each m
telo118 [61]

Answer:

The demand will drop approximately 23 T-shirt per month.

Step-by-step explanation:

Consider the provided formula.

q = 510-90p^{0.5}

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That means p=$15 and \frac{dp}{dt}=2

We need to find how fast demand will drop.

So differentiate the above function with respect to time.

\frac{dq}{dt} =0-45p^{0.5-1}\frac{dp}{dt}

\frac{dq}{dt} =-45p^{-0.5}\frac{dp}{dt}

Substitute the respective values as shown:

\frac{dq}{dt} =-45(15)^{-0.5}(2)

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Hence, the demand will drop approximately 23 T-shirt per month.

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4 years ago
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Answer:-180

Step-by-step explanation:

7 0
3 years ago
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