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klio [65]
2 years ago
11

Can you please tell me what’s wrong in this plot? I can’t see what.

Mathematics
1 answer:
Readme [11.4K]2 years ago
7 0

Answer:

The Upper Quartile would not be 59.  It would be 60.5.

Step-by-step explanation:

The Upper Quartile would not be 59.  It would be 60.5.

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Please help. Write as a single logarithm, a) log(13)+log(4) b) log(small 5)(14)-log(small 5)(2)
dsp73

Answer:

a) \log 52

b) \log_57

Step-by-step explanation:

Use logarithm properties:

\log_ab+\log_ac=\log_a(b\cdot c)\\ \\\log_ab-\log_ac=\log_a\dfrac{b}{c}

Then

a) \log 13+\log 4=\log 13\cdot 4=\log 52

b) \log_514-\log _52=\log _5\dfrac{14}{2}=\log _57

7 0
3 years ago
Please helppp meee I need it done noww
bearhunter [10]

Answer:

7/2

Step-by-step explanation:

3 wholes is equal to 6 halves plus a half equals 7 halves

6 0
3 years ago
この問題を最も簡単に解決する. 不適切な回答はありません.
Dafna1 [17]

japones ^^

look you have to multiply

8 cm x 6cm

20cm x 6 cm

and the answer that comes out of the multiplication is the correct one

4 0
3 years ago
Limit as x approaches 9 of x^2 -81/sqrt of x - 3
Ipatiy [6.2K]

Answer:

108

Step-by-step explanation:

Limit as x approaches 9 of x^2 -81/sqrt of x - 3

First substitute x into the expression

= 9²-81/√9 - 3

= 81-81/3-3

= 0/0 (indeterminate)

Apply l'hospital rule

= lim x -> 9 d/dx(x²-81)/√x - 3

= lim x -> 9 2x/1/2√x

Substitute x = 9

= 2(9)/1/2√9

=18/1/(2(3)

=18 × 6/1

= 108

Hence the limit of the function is 108

7 0
3 years ago
I'll give brainliest
erma4kov [3.2K]

Answer:

I think its D sorry if I get it wrong

Step-by-step explanation:

6 0
3 years ago
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