Get this equation into y=mx+b form.
y-2=-3(x-4)
y-2=-3x+12
y=-3x+12+2
y=-3x+14
Hope this helps!
And just a note, this is provided in point-slope formula, meaning there is a point on the line, (4,2), based on the initial equation.
Answer:
x = 11/10
Step-by-step explanation:
we have from statement:
-1=1 - 4(-5+4x) – 4x
we apply distributive property:
-1 = 1 -4*(-5) -4*(4x) -4x
so we have:
-1= 1+20 -16x -4x
-1 = 21 -20x
-22=-20x
so we have:
x=22/20
x=11/10
we can substitute the x value found:
-1 = 1 - 4(-5+4*(11/10)) – 4*(11/10)
-1 = 1+20 -17.6 -4.4
-1 =21 -22
so we have:
-1 = -1
<u>Answer:</u>
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answer = CI = 3108 RUPEES
<u>Step-by-step explanation:</u>
i am doing the method in which u find the simple interest of first year then second year.
SI FOR 1ST YEAR= P X R X T / 100
SI = 2700 X 20 X 2 / 3 X 100 ( RATE OF INTEREST IS 20 / 3)
SI = 108000/300
SI = 360
SI FOR SECOND YEAR =
P = 2700 + 360= 3060
SI = 3060 X 20 X 2 / 300
SI= 122400 / 300
SI = 408
COMPOUND INTEREST (CI) = PRINCIPLE + SI OF 2ND YEAR
CI = 2700 + 408
CI = 3108 RUPEES
or u can solve be the method
CI = amount - principle
Amount= principle x (change in ratio) raised to time
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Answer:
y = 3/2*x - 5
Step-by-step explanation:
Lets say that P1=(6,4) and P2=(4,1) and that the form of the equation must be y=m*x+b where m is the slope and b the independent variable. Then having two given points we can use the slope formula to find the slope value as:
P1=(x1,y1) and P2=(x2,y2)
slope formula ---> m=(y2-y1)/(x2-x1)
Replacing the given points ---> m=(1-4)/(4-6) = 3/2
then replacing the slope value obtained:
y = 3/2*x + b
Now lets find the value of b. For this we have to replace in the equation a point it can be P1 or P2, i will replace P2:
1 = 3/2*4 + b
1 = 6 + b
1 - 6 = b
-5 = b
therefore the line equation is:
y = 3/2*x - 5
