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KonstantinChe [14]
3 years ago
5

Which 2 equations would you use to solve this system?

Mathematics
1 answer:
slega [8]3 years ago
4 0

Answer:

x-y=4

and

x+y=32 is <u>your</u><u> </u><u>equation</u>

<u>d</u><u>i</u><u>f</u><u>f</u><u>e</u><u>r</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>w</u><u>o</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>=</u><u>x-y</u><u> </u><u>is</u><u> </u><u>equal</u><u> </u><u>to</u><u> </u><u>4</u>

<u>s</u><u>u</u><u>m</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>w</u><u>o</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u>=</u><u>x</u><u>+</u><u>y</u><u> </u><u>i</u><u>s</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>l</u><u> </u><u>t</u><u>o</u><u> </u><u>3</u><u>2</u>

<u>x</u><u>-</u><u>y</u><u>=</u><u>4</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>(</u><u>1</u><u>)</u>

<u>x</u><u>+</u><u>y</u><u>=</u><u>3</u><u>2</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>(</u><u>2</u><u>)</u>

<u>a</u><u>d</u><u>d</u><u>i</u><u>n</u><u>g</u><u> </u><u>equation</u><u> </u><u>1</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>2</u>

<u>x</u><u>-</u><u>y</u><u> </u><u>+</u><u>x</u><u>+</u><u>y</u><u>=</u><u>4</u><u>+</u><u>3</u><u>2</u>

<u>2</u><u>x</u><u>=</u><u>3</u><u>6</u>

<u>x</u><u>=</u><u>3</u><u>6</u><u>/</u><u>2</u><u>=</u><u>1</u><u>6</u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>

<u>s</u><u>u</u><u>b</u><u>s</u><u>t</u><u>i</u><u>t</u><u>u</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>y</u><u> </u><u>in</u><u> </u><u>equation</u><u> </u><u>1</u>

<u>1</u><u>6</u><u>-</u><u>y</u><u>=</u><u>4</u>

<u>1</u><u>6</u><u>-</u><u>4</u><u>=</u><u>y</u>

<u>y</u><u>=</u><u>1</u><u>2</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>

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Answer:

The capacity of the container is 2546.78 cm³.

Step-by-step explanation:

The volume of the frustum of a cone is:

\text{Volume}=\frac{\pi h}{3}\cdot[R^{2}+Rr+r^{2}]

The information provided is:

r = 16/2 = 8 cm

R = 24/2 = 12 cm

h = 8 cm

Compute the capacity of the container as follows:

\text{Volume}=\frac{\pi h}{3}\cdot[R^{2}+Rr+r^{2}]

            =\frac{\pi\cdot8}{3}\cdot[(12)^{2}+(12\cdot 8)+(8)^{2}]\\\\=\frac{8\pi}{3}\times [144+96+64]\\\\=\frac{8\pi}{3}\times304\\\\=2546.784445\\\\\approx 2546.78

Thus, the capacity of the container is 2546.78 cm³.

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Sammie worked at the pizza place last Monday and brought home $60. If he makes $8.50 per hour and earned $13.25 in tips, how man
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Answer:

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Step-by-step explanation:

Currently, the equation is 60=8.50h+13.25 and h stands for the hours that Sammie worked. So, you need to solve for h by first subtracting 13.25 (his tips) and getting the amount that he received for the hours that he worked.

You should now have 46.75=8.50h

Our final step, is to divide 46.75 by 8.50 to get h by itself and determine the total hours that Sammie worked.

In the end, you should come out with h=5.5, which means that Sammie worked 5.5 hours.

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