Answer:
The value would be
Step-by-step explanation:
What is the value of x in: 4x+3y=12 and 2x-3y=-30 *
4x + 3y
The answer is x = 2 - 3y = 4
3y = 30
So 2x + 3y = 12 is
X = 3 - 3y/4
2x - 3y = 30
X = 15 + 3y/2
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The shaded area is 299.59un^2.
Answer:
He should enter the lottery
Step-by-step explanation:
If A and B are independent, then
.
a.



b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:



c. DeMorgan's law can be used here too:



Answer:

Step-by-step explanation:
We want to find

This can be rewritten as;


Recall that; 

We evaluate now to obtain;
