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3 years ago

We have that 2a+1=1 and b-a=1. What is the value of b?

Mathematics

2 answers:

Margaret [11]3 years ago

8 0

Answer:

b=1

Step-by-step explanation:

2a+1 =1

Subtract 1 from each side

2a+1-1 = 1-1

2a=0

a=0

Now find b from the second equation

b-a =1

b-0=1

b=1

juin [17]3 years ago

8 0

Answer:

Equation: 2a+1=1

Subtract 1 from both sides: 2a=0

Divide by 2: a=0

Equation: b-a=1

Substitute: b-0=1

Combine: b=1

So, b=1.

Let me know if this helps.

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Triangle XYZ, XY= 80, ZY= 64 XZ= 48 what is the cosine

SVETLANKA909090 [29]

Answer:

$cos=\frac{4}{5}$

Step-by-step explanation:

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Looking at my picture then:

$cos=\frac{64}{80} \\cos=\frac{8}{10} \\cos=\frac{4}{5}$ .

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4 years ago

Find the volume of a right rectangular prism if the dimensions of the base are 6.8 centimeters by 12.5 centimeters and the heigh

Archy [21]

Answer:

6.8 x 12.5 x 13 = 1105

Step-by-step explanation:

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2 years ago

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nevsk [136]

F is proportional to 1/x^2
distance = x
A reduction of 25 percent = 0.75x
Let’s put this in place of x
F = 1/(0.75x)^2
And simplify
F = 1/0.5625x^2

So you need to find the percentage increase from 1/x^2 to 1/0.5625x^2

So what does 1/x^2 multiply by to give 1/0.5625x^2

Written as an equation it is y/x^2 = 1/0.5625x^2
Multiply both sides by x^2
y = 1/0.5625
y = 1.778 (rounded to 3 decimal points)

So the decimal multiplier is 1.778 and so the percent increase is approximately 77.8%

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2 years ago

Use the Parabola tool to graph the quadratic function. f(x)=2x^2−12x+19 Graph the parabola by first plotting its vertex and then

Debora [2.8K]

To find the vertex of our parabola, we are going to use the vertex formula: For a quadratic of the form $f(x)=x^2+bx+c$ it vertex $(h,k)$ is given by $h= \frac{-b}{2a}$ , $k=f(h)$ .
We can infet from our parabola that $a=2$ and $b=-12$ . So lets replace those values in our formula:
$h= \frac{-b}{2a}$
$h= \frac{-(-12)}{2(2)}$
$h= \frac{12}{4}$
$h=3$
$k=f(h)=2(3)^2-12(3)+19$
$k=2(9)-36+19$
$k=18-17$
$k=1$
The vertex $(h,k)$ of our parabola is $(3,1)$

Now to find our second point, we are going to evaluate our parabola at $x=0$
$f(0)=2(0)^2-12(0)+19$
$f(0)=0+0+19$
$f(0)=19$
Our second point is $(0,19)$

We can conclude that we can graph the parabola $f(x)=2x^2-12x+19$ using its vertex $(3,1)$ and the point $(0,19)$ as follows:

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%7B10%7D%5Ex%20%3D%205" id="TexFormula1" title=" {10}^x = 5" alt=" {10}^x = 5" align="absmi

My name is Ann [436]

Answer:

below

Step-by-step explanation:

10ˣ = 5

applying log to both sides

xlog 10 = log5

x = 0•699

8 0

3 years ago