Answer: (0,-1) and (1/3,0)
Step-by-step explanation:
Answer— 45/15=3 so there is 3 classes with 15 students in each class? I didn’t really understand your question but I tried!
Hope it helped!
x ≤ 6
which is A
or if not then it's B for
x ≥ 6
The function
f(x) is even
g(x) is neither even nor odd
h(x) is odd
Steps:
for an even function it holds that f(-x) = f(x):
f(-x) = (-1)^6 x^6 - (-1)^4 x^ 4 = x^6 - x^4 = f(x) => f is even
for an odd h(x) it holds that h(-x) = -h(x):
![h(-x) = (-1)^5x^5-(-1)^3x^3 = -(x^5-x^3) = -h(x) \implies h(x)\,\, \mbox{even}](https://tex.z-dn.net/?f=h%28-x%29%20%3D%20%28-1%29%5E5x%5E5-%28-1%29%5E3x%5E3%20%3D%20-%28x%5E5-x%5E3%29%20%3D%20-h%28x%29%20%5Cimplies%20h%28x%29%5C%2C%5C%2C%20%5Cmbox%7Beven%7D)
It is easy to show that g(x) does not match any of the two possibilities above.
Answer:
The equation of line with given points is 2Y - X - 5 = 0
Step-by-step explanation:
Given points are ( - 3 , 1) and (9 , 7)
Equation of line is y = mx +c
where m is the slop of line
Now m = ![\frac{y2 - y1}{x2 - x1}](https://tex.z-dn.net/?f=%5Cfrac%7By2%20-%20y1%7D%7Bx2%20-%20x1%7D)
Or, m = ![\frac{7 - 1}{9 + 3}](https://tex.z-dn.net/?f=%5Cfrac%7B7%20-%201%7D%7B9%20%2B%203%7D)
so, slop = ![\frac{6}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B12%7D)
∴ slop = ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
Now the equation of line with points ( -3 , 1) and slop m is :
Y - y1 = m ( X - x1)
Or, Y - 1 =
(X + 3)
Or, 2Y - X - 5 = 0
Hence The equation of line with given points is 2Y - X - 5 = 0 Answer