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Lana71 [14]
3 years ago
14

Help please i have no idea how to do this

Mathematics
2 answers:
vekshin13 years ago
7 0

Answer: I'm not going to give out the answers but I'm happy to explain it and help you out if you're still confused. I'm a geometry honors student rn btw just so you know my credentials.

Step-by-step explanation:

To find slope and write it in slope-intercept form you first need to know the equation and what different variables represent.

y = mx + b is the equation for slope-intercept. You need to find what m and b are to right a slope-intercept equation. for example the first problem's answer is y = \frac{-1}{2}x + 1

m is slope which is the angle that the line is at. To find slope or m, you need to choose a point on the graph. Then, count the amount of spaces vertically and horizontally until the next point on the graph. When I say point, I'm referring to a place on the graph where the line cross perfectly over the intersection of two lines on the graph. Slope is always 'rise over run' meaning it is a fraction containing the amount up or down, over the amount left or right. For example, the first problem (the one on the top left) the slope is  \frac{-1}{2} .

b is the y-intercept. The y intercept where the line crosses the y-axis which is that bold line going up and down in the middle. For example in number one, the y-intercept is 1 because it is one unit up from the origin. (the origin is 0,0, or the very middle of the graph).

Hope this helps! :)

kramer3 years ago
5 0
You need to get y = mx + b form

find the slope by counting rise over run (how many blocks does the line go up and over until the next point)

one you find the slope, slap a little x on the back end of it and u have the “mx” part

then find where the line crosses the y axis

take the y term of that point and slap it on behind the slope

and bam you have slope-intercept form
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F(x) = 4x +11; [-6, 0]<br> The domain of f(x) is
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Answer:

the answer is let a b* ban me

Step-by-step explanation:

7 0
3 years ago
Which equation represents a line that is parallel to the line y = - 4x +5?
Vikentia [17]
Y= -4x+3

slope is still the same so it would be parallel to that line. Only the y-intercept is different so it would just pass through a different point
6 0
3 years ago
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A bag contains 8 white marbles, 4 green marbles and 3 blue marbles. 2 marbles are selected at random without replacement, find t
pogonyaev

Answer:

24/225

Simplified: 8/75

Step-by-step explanation:

8 + 4 + 3 = 15

Since there are no replacements the denominator will get lower every time a marble is pulled.

First is blue which means,

3/15

The second is white,

8/15

If I'm not wrong you would multiply 3/15 and 8/15 and you get 24/225.

Simplified: 8/75

3 0
3 years ago
The data sets show the years of the coins in two collections. Derek's collection: 1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910
KATRIN_1 [288]

Answer:

Derek's collection :

Mean= 1929

Median= 1930

Range= 54

IQR = 48

MAD= 23.75

Paul's collection:

Mean= 1929

Median= 1929.5

Range= 15

IQR = 6

MAD= 3.5

Step-by-step explanation:

1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910

Mean is given by:

(1950+1952+ 1908+1902+1955+1954+1901+1910)/8

=1929

absolute deviation from mean is:

|1950-1929|= 21

|1952-1929|= 23

|1908-1929|= 21

|1902-1929|= 27

|1955-1929|= 26

|1954-1929|= 25

|1901-1929|= 28

|1910-1929|= 19

from the mean of absolute deviation gives the MAD of the data i.e.

(21+23+21+27+26+25+28+`9)/8

23.75

 

:arrange the given data to get the range and median

   1901   1902    1908   1910    1950  1952    1954   1955

The minimum value is: 1901

Maximum value is: 1955

Range is: Maximum value-minimum value

         Range=1955-1901

Range= 54

median is (1910+1950)/2

1930

   the lower set of data=

  1901   1902    1908   1910

first quartile becomes

1902+1908)/2

Q1=1905

and upper set of data is:

1950  1952    1954   1955

we find the median of the  upper quartile or third quartile is:

1952+1954)/2=1953

Q3-Q1=1953-1905=

IQR=48

 

Paul's collection:

1929, 1935, 1928, 1930, 1925, 1932, 1933, 1920

Mean is given by:

1929+1935+ 1928+ 1930+ 1925+ 1932+1933+1920)/8

1929

absolute deviation from mean is:

|1929-1929|=0

|1935-1929|= 6

|1928-1929|= 1

|1930-1929|= 1

|1925-1929|= 4

|1932-1929|= 3

|1933-1929|= 4

|1920-1929|= 9

Hence, we get:

MAD=0+6+1+1+4+3+4+9/8

28/8

3.5

arrange the data in ascending order we get:

1920   1925   1928   1929   1930   1932   1933   1935  

Minimum value= 1920

Maximum value= 1935

Range=  15 (  1935-1920=15 )

The median is between 1929 and 1930

Hence, Median= 1929.5

Also, lower set of data is:

1920   1925   1928   1929  

the first quartile or upper quartile is

1925+1928/2

1926.5

and the upper set of data is:

1930   1932   1933   1935  

We have

1932+1933)/2

1932.5

IQR is calculated as:

Q3-Q1

6

7 0
4 years ago
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Flura [38]
C = 2*pi*r
So, C = pi*d
106.76 = pi*d
106.76/pi = d
d = ~33.98
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3 years ago
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