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Karo-lina-s [1.5K]
3 years ago
6

Im stuck on these 2 questions

Mathematics
2 answers:
Kryger [21]3 years ago
8 0

Answer:

In the first question it is the 2nd table. On the second it is : No, the xost of the 9 shirts is incorrect

Goryan [66]3 years ago
3 0

Answer:In the first question it is the 2nd table

Step-by-step explanation:

You might be interested in
What is a true statement
leva [86]

Answer:

Noun. 1. true statement - a true statement; "he told the truth"; "he thought of answering with the truth but he knew they wouldn't believe it" truth.

4 0
4 years ago
How many lawns can you move with one gallon of gasoline if you maintain the rate of 1/2 gallon of gasoline per 1/4 lawn mowed
andreyandreev [35.5K]

Answer:

You can mow 1/2 a lawn with a gallon of gasoline.

Step-by-step explanation:

Start by setting the amounts equal to each other.   .5*.25.

The .5 should become a 1, so multiply it to become the answer of 1. What you do on one side should be repeated on the other side also. So then multiply .25 by 2 to get .5

7 0
4 years ago
Which of the following expressions are equivalent?
shtirl [24]

Answer:

the second option

Step-by-step explanation:

5+(1+3)= (5+1) +3

hope this helps :)

5 0
3 years ago
Solve the |4X -5|= |-X +5|
Tju [1.3M]

Answer:

IF YOU ARE SOLVING FOR X:

2,0

Step-by-step explanation:

If you simplify both sides, then isolate the variable you should get the answer

5 0
3 years ago
b) The university gym opens at 9 am on Saturday mornings. One Saturday morning at 8:55 am there are 15 students outside the gym
max2010maxim [7]

Answer:

The complete question is:

At a university, 13% of students smoke.

a) Calculate the expected number of smokers in a random sample of 100 students from this university:

b) The university gym opens at 9 am on Saturday mornings. One Saturday morning at 8:55 am there are 27 students outside the gym waiting for it to open. Should you use the same approach from part (a) to calculate the expected number of smokers among these 27 students?

Part a is easy, because is a random sample, we can expect that just 13% of these 100 students to be smokers, and 13% of 100 is 13, so we can expect 13 of those 100 students to be smokers.

b) This time we do not have a random sample, our sample is a sample of 15 students who go to the gym in the early morning, so our sample is biased. (And we do not know if this bias is related to smoking or not, and how that relationship is), so we can't use the same approach that we used in the previous part.

3 0
3 years ago
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