Let n be the smallest of these integers. The other two are then n + 2 and n + 4.
"triple of the sum of thrice the third one and twice the first one is equal to 291" is a long-winded way of saying
3 (3 (n + 4) + 2n) = 291
Solve for n :
3 (3n + 12 + 2n) + 291
3 (5n + 12) = 291
15n + 36 = 291
15n = 255
n = 17
Then the greatest of the three integers is n + 4 = 21.
You start off by multiplying the second bracket by -1 to get rid of the bracket.
So,
(2x3 + x2 - 4x) - 9x3 + 3x2 =
2x3 +x2 - 4x - 9x3 + 3x2 =
(2x3 - 9x3) + (x2 + 3x2) - 4x =
-7x3 + 4x2 - 4x
Answer:
during intesrt amrkets
Step-by-step explanation:
Answer with explanation:
<u>Part A: </u>
One solution.
The number of points of intersection represents the number of solutions. Since the two lines only intersect at one point, there is only one solution.
<u>Part B:</u>
(3, 4)
The point(s) of intersection marks the solution(s) to the lines. Since lines A and B intersect at the point (3, 4), the solution to the equation of their lines is (3, 4), or , as coordinates are written as (x, y).