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atroni [7]
3 years ago
5

PLEASE HELP ALGEBRA 1

Mathematics
2 answers:
egoroff_w [7]3 years ago
7 0
The answer is c i think
Tomtit [17]3 years ago
3 0

Answer:

C. 3

Step-by-step explanation:

This is a 30 60 90 triangle. To get from 3 rad 3 to x you need to divide rad 3 which gives you 3.

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7x <br> 5x+18 <br> Find the size of the smallest angle
allochka39001 [22]

Answer

Not sure is there supposed to be a pic?

Step-by-step explanation:

3 0
3 years ago
I am a pattern block that has 2 fewer sides than a hexagon. I have 2 pairs of parallel sides a 4 right angles. Which shape am I
never [62]

Answer:

you are a square

Step-by-step explanation:

it says " i have 2 pairs of parallel sides and 4 right angles", and typically 4 right angles make a square

8 0
3 years ago
Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE
inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to 20\ units

Part 3) The area is equal to 25\ units^{2}

Step-by-step explanation:

we have

A(5,0), B(2,4), C(-2,1),D(1,-3)

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

A(5,0),B(2,4)

substitute in the formula

d=\sqrt{(4-0)^{2}+(2-5)^{2}}

d=\sqrt{(4)^{2}+(-3)^{2}}

d=\sqrt{25}

AB=5\ units

Find the distance BC

B(2,4), C(-2,1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}

BC=5\ units

Find the distance CD

C(-2,1),D(1,-3)

substitute in the formula

d=\sqrt{(-3-1)^{2}+(1+2)^{2}}

d=\sqrt{(-4)^{2}+(3)^{2}}

d=\sqrt{25}

CD=5\ units

Find the distance AD

A(5,0),D(1,-3)

substitute in the formula

d=\sqrt{(-3-0)^{2}+(1-5)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}        

AD=5\ units

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

B(2,4),D(1,-3)

substitute in the formula

d=\sqrt{(-3-4)^{2}+(1-2)^{2}}

d=\sqrt{(-7)^{2}+(-1)^{2}}

BD=\sqrt{50}\ units        

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

BD^{2}=AD^{2}+AB^{2}

substitute

(\sqrt{50})^{2}=5^{2}+5^{2}

50=50 -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

A=b^{2}

we have

b=5\ units

A=5^{2}=25\ units^{2}

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

P=4b

we have

b=5\ units

P=4(5)=20\ units

6 0
3 years ago
Factorise 2x^2 - 9x -5
Nostrana [21]

Answer:

(x-5)(2x+1)

Step-by-step explanation:

Its called google XD

5 0
3 years ago
Find a vector equation for the line through the point P = (-3,3, -5) and parallel to the vector V= (-2,-4, -4). Assume 1-(0) =-3
CaHeK987 [17]

Answer:

The vector equation of the line is

l(t)= "-3,3,-5" + t "-2,-4,-4", where t is a parameter.

4 0
3 years ago
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