Im pretty sure it can. 20 +20 = 40. if that helps...
Answer:
Tn = 64-4n
Step-by-step explanation:
The nth term of an AP is expressed as:
Tn = a+(n-1)d
a is the common difference
n is the number of terms
d is the common difference
Given the 6th term a6 = 40
T6 = a+(6-1)d
T6 = a+5d
40 = a+5d ... (1)
Given the 20th term a20 = -16
T20 = a+(20-1)d
T20 = a+19d
-16 = a+19d... (2)
Solving both equation simultaneously
40 = a+5d
-16 = a+19d
Subtracting both equation
40-(-16) = 5d-19d
56 = -14d
d = 56/-14
d = -4
Substituting d = -4 into equation
a+5d = 40
a+5(-4) = 40
a-20 = 40
a = 20+40
a = 60
Given a = 60, d = -4, to get the nth term of the sequence:
Tn = a+(n-1)d
Tn = 60+(n-1)(-4)
Tn = 60+(-4n+4)
Tn = 60-4n+4
Tn = 64-4n
Answer:
SO you want me to figure out from year 2 or year4?
Step-by-step explanation:
I got 28 grams for this one............
The first answer is correct
C(2, -2) D(-1, -2)
because the line from point a to point b is 3 units long and 3 x 4 = 12 (area) (and 12/3=4) so, the points that are exactly 4 units down from point a and point b would be the correct answer - (2, -2) and (-1, -2)