Please help me:) this is due by tonight!

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

6 0

Answer:

$Solution,\\Here,\\Slope~of~line~y=\frac{2}{3}x+19, m_1=\frac{2}{3} \\Let~slope~of~line~passing~through~(6,2)~and~parallel~to~ y=\frac{2}{3}x+19~be~m_2.\\Using~condition~of~parallel~lines,\\m_1 = m_2\\or, m_2 = \frac{2}{3} \\Now,\\The~eq^n~of~a~line~passing~through~(6,2)~and~having~slope~\frac{2}{3}~is~given~by:\\y-2=\frac{2}{3} (x-6)\\or, 3y-6 = 2x-12\\or, 2x-3y = 12-6\\or, 2x-3y=6~is~the~required~equation$

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Find the area of an equilateral triangle with apothem 7 cm.

lbvjy [14]

So hmm check the picture below

using the 30-60-90 rule, we get that much.. .bear in mind, an equilateral triangle has all equal sides, and therefore, all equal angles, so each angle is 60°, run a median through it from the center, and you split it in half

$\bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}\qquad 
\begin{cases}
s=\textit{length of one side}\\
----------\\
s=14\sqrt{3}
\end{cases}\implies A=\cfrac{(14\sqrt{3})^2\sqrt{3}}{4}
\\\\\\
A=\cfrac{14^2\cdot 3\sqrt{3}}{4}\implies A=\cfrac{588\sqrt{3}}{4}\implies A=147\sqrt{3}$