Question

Please help me:) this is due by tonight!

Answer 1

Answer:

$Solution,\\Here,\\Slope~of~line~y=\frac{2}{3}x+19, m_1=\frac{2}{3} \\Let~slope~of~line~passing~through~(6,2)~and~parallel~to~ y=\frac{2}{3}x+19~be~m_2.\\Using~condition~of~parallel~lines,\\m_1 = m_2\\or, m_2 = \frac{2}{3} \\Now,\\The~eq^n~of~a~line~passing~through~(6,2)~and~having~slope~\frac{2}{3}~is~given~by:\\y-2=\frac{2}{3} (x-6)\\or, 3y-6 = 2x-12\\or, 2x-3y = 12-6\\or, 2x-3y=6~is~the~required~equation$