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Yuliya22 [10]
3 years ago
5

8/2z=15/60 .solve proportion.

Mathematics
2 answers:
masya89 [10]3 years ago
8 0
\frac{8}{2z}=\frac{15}{60}\ \ \ \ \ |cross\ multiply\\\\2z\cdot15=8\cdot60\\\\30z=480\ \ \ \ |divide\ both\ sides\ by\ 30\\\\\boxed{z=16}
ch4aika [34]3 years ago
4 0
\dfrac{8}{2z}=\dfrac{15}{60}\\
\dfrac{4}{z}=\dfrac{1}{4}\\
z=16
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The length of a rectangular is 5/2 unites greater then twice its width if it’s width w which expression gives the perimeter of t
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If width is w the length can be represented as 5/2+2w.

Formula for perimeter is 2l + 2w

So it would be 2w + 2(5/2 + 2w)

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OR 6w + 5



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a toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its heigh
sdas [7]

Answer:

t = 2.11 seconds

Step-by-step explanation:

A toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its height h at any given second t is modeled by the equation:

h=-16t^2+32t+48

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-16t^2+32t+48=0

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t=\dfrac{-b\pm \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-b+ \sqrt{b^2-2ac} }{2a},\dfrac{-b- \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-32+ \sqrt{(32)^2-2\times (-16)(8)} }{2\times (-16)},\dfrac{-32-\sqrt{(32)^{2}-2\times(-16)(8)}}{2\times(-16)}\\\\t=-0.11\ s, 2.11\ s

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6 0
3 years ago
a spherical balloon is deflated at a rate of 256pi/3 cm^3/sec. at what rate is the radius of the balloon changing when the radiu
Hunter-Best [27]
What you need to look for is \frac { dr }{ dt } when r=8.

Now:

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\therefore \quad \frac { dV }{ dr } =\frac { 4 }{ 3 } \pi \cdot 3{ r }^{ 2 }=4\pi { r }^{ 2 }\\ \\ \therefore \quad \frac { dr }{ dV } =\frac { 1 }{ \frac { dV }{ dr }  } =\frac { 1 }{ 4\pi { r }^{ 2 } }

And:\\ \\ \frac { dV }{ dt } =-\frac { 256\pi  }{ 3 } \\ \\ Therefore:\\ \\ \frac { dr }{ dt } =\frac { dr }{ dV } \cdot \frac { dV }{ dt }

\\ \\ =\frac { 1 }{ 4\pi { r }^{ 2 } } \cdot -\frac { 256\pi  }{ 3 } \\ \\ =-\frac { 256 }{ 12 } \cdot \frac { \pi  }{ \pi  } \cdot \frac { 1 }{ { r }^{ 2 } }

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3 0
3 years ago
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