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3 years ago

Factor as the product of two binomials (x^2 - 10x + 21)

Mathematics

2 answers:

SOVA2 [1]3 years ago

4 0

Answer:

(x - 7)(x - 3)

Step-by-step explanation:

Given

x² - 10x + 21

Consider the factors of the constant term (+ 21) which sum to give the coefficient of the x- term (- 10)

The factors are - 7 and - 3 , since

- 7 × - 3 = + 21 and - 7 - 3 = - 10, thus

x² - 10x + 21 = (x - 7)(x - 3) ← in factored form

kozerog [31]3 years ago

3 0

Answer:

Step-by-step explanation:

x^2-10x+21

(x-7)(x-3)

find the 2 numbers that when multiplied make the last number or +21 and when combined make the middle number of -10. -7*-3 = 21 and -7+-3=10

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3 years ago

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2 years ago

Which best describes the graphs of the line that passes through (−12, 15) and (4, −5), and the line that passes through (−8, −9)

konstantin123 [22]

Answer:

C) They are perpendicular lines.

Step-by-step explanation:

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3 years ago

Read 2 more answers

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DedPeter [7]

So

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use a piecewise function maybe

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k, sso 46>40 so

840+1.5(21(46-40))
840+1.5(21(6))
840+1.5(126)
840+189
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A. 840+1.5(21(x-40))
B. $1029

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2 years ago

Write the six step in division

joja [24]

Answer:

Divide the tens column dividend by the divisor. Multiply the divisor by the quotient in the tens place column. Subtract the product from the divisor

Step-by-step explanation:

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2 years ago

Factor as the product of two binomials (x^2 - 10x + 21)​

Factor as the product of two binomials (x^2 - 10x + 21)