Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
Answer:
y = 3x
Step-by-step explanation:
Slope equation:
y2 - y1
--------
x2 - x1
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6 - 0 6
m = ----------- = ----- = 3
2 - 0 2
Your slope is 3.
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Equation:
y = mx + b
Plug in the slope and you get:
y = 3x + b
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Now to find b, you can use either coordinate point. So I will show you both ways :)
<u>(0,0)</u> <u>(2,6)</u>
0 = 3(0) + b 6 = 3(2) + b
Multiply 0 and 3 Multiply 2 and 3
0 = 0 + b 6 = 6 + b
Subtract 0 to 0 Subtract 6 from 6
0 = b 0 = b
There is no y-intercept
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Your answer: y = 3x
Hope this helped :)
52.7 ÷ 4.25 = 12.4
Hope that helps ....
PLEASE HELP MEEEEEEEE IM BEGGING
You would divide 32 divided by 8 which is 4 then you would multiply 6 times 4 and your answer would be 24 feet deep.
