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podryga [215]
3 years ago
5

Please help with both and leave a small explanation! I wanna double check my answers!

Mathematics
1 answer:
jeka57 [31]3 years ago
3 0

Answer:

(1)Hoops shadow would be 6 ft (2) model would be 3 cms

Step-by-step explanation:

9 / 3 = 3   3 x 2 = 6 ft

15 / 5 =3    3 x 1 = 3 cm

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zheka24 [161]
Where is your question?
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3 years ago
the computer lab is removing the three broken computers and adding 13 wireless devices about what percent of the lab are wireles
andreyandreev [35.5K]
So the fraction would be 13/100 so now divide it and then u should get 7.6923076923



5 0
3 years ago
Read 2 more answers
What is the solution to this equation?
tresset_1 [31]

Answer:

x = 9

Step-by-step explanation:

First, we want to isolate variable x on the left side of the equation. We can do this by adding 13 to both sides.

x - 13 + 13 = - 4 + 13

x = 9

8 0
3 years ago
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Explain why all squares are similar????? and please help with question below!!!!!!!!!!!!!
Oliga [24]
That's not a squre
anyway, we use ratios
base:person to corner=28:8
height to height=x:5
so
28/8=x/5 becasue same ratio
28/8=14/4=7/2
7/2=x/5
multiply
35/10=2x/10
35=2x
divide 2
17.5=x

x=17.5 feet
5 0
3 years ago
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
borishaifa [10]

Answer:

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

Step-by-step explanation:

Air containing 0.04% carbon dioxide

V, volume of room is 6000 ft3.

Q, rate of air 2000 ft3/min,

initial concentration of 0.4% carbon dioxide,

determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes?

firstly, we find the time taken for air to completely filled the room

Q = V/t

t = V/Q = 6000/2000 = 3min

so, its take 3mins for air to be completely filled in the room and for exhaust air to move out.

there is  an initial concentration of 0.4% carbon dioxide, and the air pump in is 0.04%.

therefore,

3mins = 0.04% of CO2

3*60 =180sec = 0.04%

1sec = 0.04/180 = 0.00022%/sec

so at any time the concentration of CO2 is 0.4 + 0.00022 =0.40022%/sec

What is the concentration at 10 minute

the concentration at 10minutes = the concentration for 1minute because at every minutes, the concentration moves in is moves out. = concentration for 2000ft3.

for 0.04% = 6000ft3

   ?          = 2000ft3

              = 2000* 0.04)/6000 =0.0133%

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

4 0
3 years ago
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