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Luba_88 [7]
3 years ago
10

A radio station claims that the amount of advertising each hour has a mean of 15 minutes and a standard deviation of 2.9 minutes

. You listen to the radio station for 1 hour and observe that the amount of advertising time is 16 minutes. Calculate the ​z-score for this amount of advertising time. Round to the nearest hundredth.
Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

Answer:

0.1296

Step-by-step explanation:

Use the normpdf function available on basic calculators:

normpdf(16,15,2.9) = 0.1296

This is the z-score representing 16 minutes.  Note that 16 is just one point above 15, so this small positive z-score makes sense.

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