Answer:
dV/dt = 3×10^2 × 0.5 = 150 in^3/sec
the volume of the cube is increasing at 150in^3/sec
Step-by-step explanation:
Volume V = length l^3
V = x^3
Differentiating both sides;
dV/dt = 3x^2 dv/dt
Given;
x = 10 in
dx/dt = 0.5 in/sec
dV/dt = 3×10^2 × 0.5 = 150 in^3/sec
the volume of the cube is increasing at 150in^3/sec
Answer:
6? i am soooo confused
Step-by-step explanation:
Answer:
-66
Step-by-step explanation:
There will be $66 left after the $12 spent on lunch. 66 + -66 = 0
Answer:
Part A:
(1) x + y = 95
(2) x = y + 25
Part B:
The number of minutes Eric spends playing volleyball each day is 35 minutes
Part C:
It is not possible for Eric to have spent exactly 35 minutes playing basketball
Step-by-step explanation:
The total time Eric plays basketball and volleyball = 95 minutes
The time duration Eric plays basket ball = x
The time duration Eric plays volleyball = y
Part A:
The pair of relationships between the number of minutes Eric plays basketball (x) and the number of minutes he plays volleyball (y) are;
(1) x + y = 95
(2) x = y + 25
Part B:
By substituting the value of x in equation (2) into equation (1), we have;
x + y = (y + 25) + y = 95
2·y + 25 = 95
2·y = 95 - 25 = 70
y = 70/2 = 35 minutes
Therefore, Eric spends 35 minutes playing volleyball every day
Part C:
It is not possible for Eric to have spent only 35 minutes playing basketball because, given that he plays basketball for 25 minutes longer than he plays volley, the number of minutes he spends playing volleyball will then be given as follows;
x = y + 25
35 = y + 25
y = 35 - 25 = 10 minutes
The total time = x + y = 10 + 35 = 45 minutes ≠ 95 minutes.
6 in the hundreds place = 600
6 in the tens place =60
