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3 years ago

Combine terms: 12a + 26b -4b – 16a

Mathematics

2 answers:

liq [111]3 years ago

7 0

Answer:

Step-by-step explanation:

combine terms: 12a + 26b -4b – 16a

12a - 16a + 26b - 4b
-4a + 22b

Sergeu [11.5K]3 years ago

4 0

Answer:

-4a+22b

Step-by-step explanation:

If you add the terms with "a" (12a and -16a) you get -4a.

If you add the terms with "b" (26b and -4b) you get a positive 22b.

You can write the answer as -4a+22b or 22b-4a.

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((81x^3 y^(-1/3))^1/4)/(x^2 y)^1/4 simplify

malfutka [58]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
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\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
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$\bf \cfrac{\left( 81x^3y^{-\frac{1}{3}} \right)^{\frac{1}{4}}}{(x^2y)^{\frac{1}{4}}}\implies \cfrac{81^{\frac{1}{4}}x^{3\cdot {\frac{1}{4}}}y^{-\frac{1}{3}\cdot {\frac{1}{4}}}}{x^{2\cdot {\frac{1}{4}}}y^{\frac{1}{4}}}\implies
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7 0

3 years ago

Solution set for 6a^2-a-5=0

VMariaS [17]

(step 1) (6a+5)(a-1)=0

(step 2) 6a+5=0 or a-1=0

answer is
a= -5/6 or a= 1
i hope this helps! ;)

6 0

3 years ago

Read 2 more answers

You have 2,112 grams of a radioactive kind of mercury. How much will be left after 188 days if it's half-life is 47 days?

Anastasy [175]

Answer:

132 g

Step-by-step explanation:

Initial amount = 2112 g
Time = 188 days
Half-life = 47 days

188 days / 47 days = 4 periods

<u>Mercury left after 188 days:</u>

2112 * (1/2)^4 =
2112* 1/16 =
2112/16 =
132 g

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3 years ago

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Sveta_85 [38]

Answer:

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Step-by-step explanation:

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3 years ago

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taurus [48]

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Answer:

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Step-by-step explanation:

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3 years ago