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Arisa [49]
3 years ago
5

A train is traveling 55 mph to a destination that is 330 mi away. The function f(x)=−55x+330f(x)=−55x+330 represents the remaini

ng number of miles to the destination after x hours of travel. What is the practical domain of the function f?
Mathematics
1 answer:
miv72 [106K]3 years ago
7 0
F(x) = - 55x + 330

The domain is the set of possible input-values, i.e. x-values.

You know that f(x) cannot bebigger than 330 not lower than zero, then construct the inequality:

0 ≤ f(x) ≤ 330

0 ≤ - 55x + 330 ≤ 330

Multilply by - 1 and change the inequality signs:

0 ≥ 55x - 330 ≥ -330

Add 330 to all the members

330 ≥ 55x ≥ 0

Divide by 55

6 ≥ x ≥ 0 => 0 ≤ x ≤ 6

The the possible x-values (practical domain) is all the real numbers between 0 and 6 inclusive.
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1. which of the following is an example of an integer?
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Read 2 more answers
What is the simplified form of
umka21 [38]

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

Answer:

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4

Step-by-step explanation:

Given the expression

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)

solving the expression

=-7x^0+5x^2-x+6-\left(-8x^2+x+3\right)

apply the rule: a^0=1,\:a\ne \:0

=-7+5x^2-x+6-\left(-8x^2+x+3\right)

=-7+5x^2-x+6+8x^2-x-3

simplify

=13x^2-2x-4

Therefore, the simplified form is:

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

8 0
3 years ago
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