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3 years ago

PLEASE HELP!!! I am stuck!

Mathematics

2 answers:

quester [9]3 years ago

8 0

1//3 is the largest

labwork [276]3 years ago

4 0

1/3 has the largest value.

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Lynn gave her hair stylist a $5.10 tip. The tip was 17% of the cost of the haircut. Write an equation to find b, the cost of

SSSSS [86.1K]

Answer:

5.10 = .17 × b

or possibly b = 5.10 × 1.17 (but go with the first one)

6 0

3 years ago

Read 2 more answers

Please I need help. Use the diagram to find the measure of LM.

meriva

Answer:

Step-by-step explanation:

<h2> because it is between 100 & 120 </h2>

7 0

1 year ago

Solve for x.<br> 4x^2 − 40x + 94 = 0

Karo-lina-s [1.5K]

Answer: x = 41.22 and 38.78

Step-by-step explanation:

Given the equation

4x² - 40x + 94 = 0

Using the general formula

x = -b+/-√b²-4ac/2a

Where a = 4, b= -40 c= 94

x = -(-40)+/-√(-40)²-4(4)(94)/2(4)

x = 40+/-√1600-1504/8

x = 40 +/-√96/8

x = 40 +/-9.8/8

x = 40+/-1.22

x= 40+2.22 = 41.22

and x = 40 -1.22

x = 38.78

8 0

2 years ago

A large tank is partially filled with 100 gallons of fluid in which 20 pounds of salt is dissolved. Brine containing 1 2 pound o

sertanlavr [38]

Answer:

Step-by-step explanation:

From the given information:

$R_{in} = ( \dfrac{1}{2} \ lb/gal) (6)\ gal /min \\ \\R_{in} = 3 \ lb/min$

Given that the solution is pumped at a slower rate of 4gal/min

Then:

$R_{out} = \dfrac{4A}{100+(6-4)t}$

$R_{out}= \dfrac{2A}{50+t}$

The differential equation can be expressed as:

$\dfrac{dA}{dt}+ \dfrac{2}{50+t}A = 3 \ \ \ ... (1)$

Integrating the linear differential equation; we have::

$\int_c \dfrac{2}{50 +t}dt = e^{2In |50+t|$

$\int_c \dfrac{2}{50 +t}dt = (50+t)^2$

multiplying above integrating factor fields; we have:

$(50 +t)^2 \dfrac{dA}{dt} + 2 (50 + t)A = 3 (50 +t)^2$

$\dfrac{d}{dt}\bigg [ (50 +t)^2 A \bigg ] = 3 (50 +t)^2$

$(50 + t)^2 A = (50 + t)^3+c$

A = (50 + t) + c(50 + t)²

Using the given conditions:

A(0) = 20

⇒ 20 = 50 + c (50)⁻²

-30 = c(50) ⁻²

c = -30 × 2500

c = -75000

A = (50+t) - 75000(50 + t)⁻²

The no. of pounds of salt in the tank after 35 minutes is:

A(35) = (50 + 35) - 75000(50 + 35)⁻²

A(35) = 85 - $\dfrac{75000}{7225}$

A(35) =69.6193 pounds

A(35) $\simeq$ 70 pounds

Thus; the number of pounds of salt in the tank after 35 minutes is 70 pounds.

6 0

3 years ago

The lengths of the sides in a triangle are consecutive odd integers. If the perimeter of the triangle is 57, how

BlackZzzverrR [31]

Each side would be measure 19

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3 years ago