Help with the graph please.

If you triple 4 and subtract 2 each day, how many day until you have zero?

weqwewe [10]

I'll take it that it's implied that we're only subtracting 2 everyday, and only triple 4 once.

So, let's break this down.

Triple 4. This means to multiply by 3, or self-add 4 three times.

It should look like this:
4 + 4 + 4
or
4(3) or 4 • 3.

Let's go with the addition path, as it's easier to understand.
4 + 4 + 4. (Total of three 4's)
4 + 4 = 8 (Get rid of two 4's)
We are now left with one 4.
Add it to our current sum, 8.
8 + 4 = 12.

We now have 12 total.
However, since we're subtracting 2 EACH day, we'll have to divide 12 by 2 to find how many days until we reach zero.
12 / 2 = 6.

It will take 6 days for you to have zero.

I hope this helps!

6 0

3 years ago

HELPPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!

Shalnov [3]

I’m pretty sure it would be C= 81.64

7 0

3 years ago

If A, B, and C are integers between 1 and 10 (inclusive), how many different combinations of A, B, and C exist such that A

Marianna [84]

$\fontsize{18}{10}{\textup{\textbf{The number of different combinations is 120.}}}$

Step-by-step explanation:

A, B and C are integers between 1 and 10 such that A<B<C.

The value of A can be minimum 1 and maximum 8.

If A = 1, B = 2, then C can be one of 3, 4, 5, 6, 7, 8, 9, 10 (8 options).

If A = 1, B = 3, then C has 7 options (4, 5, 6, 7, 8, 9, 10).

If A = 1, B = 4, then C has 6 options (5, 6, 7, 8, 9, 10).

If A = 1, B = 5, then C has 5 options (6, 7, 8, 10).

If A = 1, B = 6, then C has 4 options (7, 8, 9, 10).

If A = 1, B = 7, then C has 3 options (8, 9, 10).

If A = 1, B = 8, then C has 2 options (9, 10).

If A = 1, B = 9, then C has 1 option (10).

So, if A = 1, then the number of combinations is

$n_1=1+2+3+4+5+6+7+8=\dfrac{8(8+1)}{2}=36.$

Similarly, if A = 2, then the number of combinations is

$n_2=1+2+3+4+5+6+7=\dfrac{7(7+1)}{2}=28.$

If A = 3, then the number of combinations is

$n_3=1+2+3+4+5+6=\dfrac{6(6+1)}{2}=21.$

If A = 4, then the number of combinations is

$n_4=1+2+3+4+5=\dfrac{5(5+1)}{2}=15.$

If A = 5, then the number of combinations is

$n_5=1+2+3+4=\dfrac{4(4+1)}{2}=10.$

If A = 6, then the number of combinations is

$n_6=1+2+3=\dfrac{3(3+1)}{2}=6.$

If A = 7, then the number of combinations is

$n_7=1+2=\dfrac{2(2+1)}{2}=3.$

If A = 3, then the number of combinations is

$n_8=1.$

Therefore, the total number of combinations is

$n\\\\=n_1+n_2+n_3+n_4+n_5+n_6+n_7+n_8\\\\=36+28+21+15+10+6+3+1\\\\=120.$

Thus, the required number of different combinations is 120.

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Link : https://brainly.in/question/4909567.

8 0

4 years ago

The radius of a right circular cone is increasing at a rate of 1.4 in/s while its height is decreasing at a rate of 2.4 in/s. At

pychu [463]

Answer:

The volume is increasing at a rate of 27093 cubic inches per second.

Step-by-step explanation:

Volume of a cone:

THe volume of a cone, with radius r and height h, is given by:

$V = \frac{1}{3} \pi r^2h$

In this question:

We have to differentiate implictly is function of t, so the three variables, V, r and h, are differenciated. So

$\frac{dV}{dt} = \frac{\pi r^2}{3}\frac{dh}{dt} + \frac{2\pi rh}{3}\frac{dr}{dt}$

The radius of a right circular cone is increasing at a rate of 1.4 in/s while its height is decreasing at a rate of 2.4 in/s.

This means that $\frac{dr}{dt} = 1.4, \frac{dh}{dt} = -2.4$

Radius is 140 in. and the height is 186 in.

This means that $r = 140, h = 186$

At what rate is the volume of the cone changing?

$\frac{dV}{dt} = \frac{\pi r^2}{3}\frac{dh}{dt} + \frac{2\pi rh}{3}\frac{dr}{dt}$

$\frac{dV}{dt} = \frac{\pi (140)^2}{3}(-2.4) + \frac{2\pi 140*186}{3}1.4$

$\frac{dV}{dt} = -0.8\pi(140)^2 + 62*2\pi*1.4*140$

$\frac{dV}{dt} = 27093$

Positive, so increasing.

The volume is increasing at a rate of 27093 cubic inches per second.

4 0

3 years ago

What is the volume of the figure

lana [24]

Answer:

The answer would be D. 14 cm block

Step-by-step explanation:

if you count all the blocks the you get 14. this is the total number of cm blocks.

6 0

3 years ago

Read 2 more answers