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ollegr [7]
3 years ago
11

2. Reflect XYZ about the line y=1 making RQL. List all congruent sides and angles:

Mathematics
1 answer:
mina [271]3 years ago
7 0

Answer:

              ∠RQL≅∠XYZ

              ∠QRL≅∠YXZ

              ∠RLQ≅∠XZY

           RQ≅XY,  RL≅XZ,  QL≅YZ        

Step-by-step explanation:

First we draw the line y=1 (parallel to x-axis and going throu y=1)

To reflect point Y over the line y=1 we draw a line from that point perpendicular to the line of reflecting (y=1), measure the distance from the point Y to the line y=1, and then measure the same distance on the other side of the line y=1 to get reflected point. Mark it. The angle at the reflected point will be congruent to ∠Y

The same goes for points X and Z

Angles at given and reflected point are congruent.

Sides of triangle are congruent if they lay between two congruent angles.

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Write an explicit formula for the arithmetic sequence 15.6, 15, 14.4, 13.8,..., and then find the 32nd term.
uysha [10]

Answer: the 32nd term is - 3

Step-by-step explanation:

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + d(n - 1)

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 15.6

d = 15 - 15.6 = 14.4 - 15 = - 0.6

n = 32

The explicit formula for the arithmetic sequence is

Tn = 15.6 - 0.6(n - 1)

We want to determine the value of the 32nd term, T32. Therefore,

T32= 15.6 - 0.6 (32 - 1)

T32 = 15.6 - 18.6

T32 = - 3

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3 years ago
I need help pleasee please
Volgvan

Answer:

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7 0
3 years ago
In a class the ratio of boys to girls is 4:3 30% of the boys are left handed.
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The linear equation y = mx + b contains the point (4, -2) and is perpendicular to the
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A linear equation is represented as: y = mx + b.

The equation of the line is: y =3x - 14

First, we calculate the slope (m) of 6x + 18y = 11

Make y the subject

18y = -6x + 11

Divide by 18

y = -\frac{1}{3}x + \frac{11}{18}

In y = mx + b

m \to slope

So, the slope of y = -\frac{1}{3}x + \frac{11}{18} is:

m = -\frac 13

Since, the line is perpendicular to 6x + 18y = 11

The slope of the line is:

m_1 = -\frac{1}{m}

So, we have:

m_1 = -\frac{1}{-1/3}

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y =m(x - x_1) + y_1

This gives:

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y =3x - 12 -2

y =3x - 14

Hence, the linear equation is:

y =3x - 14

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brainly.com/question/11897796

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