L = length
w = width
r = diagonal, or hypotenuse
In order to solve this, you must use the Pythagorean theorem (a^2 + b^2 = c^2)
L = w + 9 = a
w = ? = b
r = 10 + w = c
Solve like so:
a^2 + b^2 = c^2
(w + 9)^2 + w^2 = (10 + w)^2
(w + 9)(w + 9) + w^2 = (10 + w)(10 +w)
w^2 + 18w + 81 + w^2 = w^2 + 20w + 100
2w^2 + 18w + 81 = w^2 + 20w + 100
w^2 + 18w + 81 = 20w + 100
w^2 + 81 = 2w + 100
w^2 - 19 = 2w
2 = w - 19/w
w = 2 + 19/w
w ends up being equal to 5.47 as a decimal answer. The work to solve this equation further would require me to spend another couple hours to present. So if you wish to see how this is done, go to quickmath.com.
Use the point-slope formula:
y+3 = (-4)(x+8)
Answer:
C. f(x) = 40(1/4)^x
Step-by-step explanation:
Check all the options:
When x = 0
A. f(x) = 1/4(40)^x
f(x) = 1/4(40)^0
f(x) = 1/4(1)
f(x) = 1/4
When x = 0
B. f(x) = 1/2(40)^x
= 1/2(40)^0
= 1/2(1)
f(x) = 1/2
When x = 0
C. f(x) = 40(1/4)^x
= 40(1/4)^0
= 40(1)
= 40
When x = 0
D. f(x) = 4(1/3)^x
= 4(1/3)^0
= 4(1)
= 4
You don’t have to worry about identity thief
