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riadik2000 [5.3K]
3 years ago
14

What dy did mrter thother king dye

Mathematics
2 answers:
Vesnalui [34]3 years ago
8 0
If your asking why he got shot
If your asking when it was April 4 1968

Hope it helps
Couldn’t understand what u wrote
Pachacha [2.7K]3 years ago
6 0
Can you explain who you’re referring to specifically, I can’t read what you’re saying
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How do you write 1 1/2 as a fraction and a percent?
vovikov84 [41]
1 1/2 is already a fraction. It's improper fraction is 3/2. It's percentage is is 150%.
6 0
3 years ago
Read 2 more answers
Are the lines 2y-10x=4 and y-2=5x parallel ??
aleksandrvk [35]
Well,

If the slope of the lines are the same, then the lines are parralel.

We need to manipulate 2y - 10x = 4 into y = mx + b form.

Add 10x to both sides
2y = 10x + 4

Divide both sides by 2
y = 5x + 2

Do the same thing with the other equation.

Add 2 to both sides
y = 5x + 2

y = 5x + 2

It appears that, not only are they parallel, but they lie on exactly the same line! If this was a System of Simultaneous Linear Equations, then there would be an infinite number of solutions!<span />
5 0
4 years ago
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A certain test preparation course is designed to help students improve their scores on the USMLE exam. A mock exam is given at t
bogdanovich [222]

Answer:

The critical value is T = 4.604.

The 99% confidence interval for the average net change in a student's score after completing the course is (6.236, 22.164).

Step-by-step explanation:

The first step to solve this question is finding the sample mean and sample standard deviation:

14,11,18,9,19

Sample mean is sum of all values divided by the number of values. Thus:

\overline{x} = \frac{14+11+18+9+19}{5} = 14.2

The sample standard deviation is the square root of the division of the sum of the subtractions squared of each value and the mean, and the number of values. Thus:

s = \sqrt{\frac{(14-14.2)^2+(11-14.2)^2+(18-14.2)^2+(9-14.2)^2+(19-14.2)^2}{5}} = 3.868

Confidence interval:

We have the standard deviation for the sample, and so we use the t-distribution to build the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 5 - 1 = 4

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 4 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 4.604.

The critical value is T = 4.604.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 4.604\frac{3.868}{\sqrt{5}} = 7.964

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 14.2 - 7.964 = 6.236.

The upper end of the interval is the sample mean added to M. So it is 14.2 + 7.964 = 22.164.

The 99% confidence interval for the average net change in a student's score after completing the course is (6.236, 22.164).

8 0
3 years ago
Oab.......................
Tanzania [10]

Answer:

ok....…....…...…..…..……..…

Step-by-step explanation:

4 0
3 years ago
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Stan and hilda can mow the lawn in 45 min if they work together. if hilda works twice as fast as stan, how long would it take st
Leona [35]
It would take Stan 30 minutes and Hilda 15 minutes
7 0
3 years ago
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