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Ghella [55]
4 years ago
12

The high school, middle school, and elementary school are all on the same road. The distance from the high school to the middle

school can be represented by the expression 8.7x2+11.9x+3.5 . The distance from the middle school to the elementary school can be represented by the expression 3.23x2+2.7x+0.75 . What is the total distance from the high school to the elementary school?
Mathematics
2 answers:
lara31 [8.8K]4 years ago
8 0
I know how to work it out. The only problem is that your expressions don't make sense because you put the multiplication sign next to the addition sign and that can't work.
Margarita [4]4 years ago
6 0

Answer:

what do you mean in this question plus what are you asking I don't get it at all.

Step-by-step explanation:

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Starting at the park, Jake bikes 3 blocks north, 4 blocks east, 4 blocks south, 7 blocks west, and 1 block north. How many block
yan [13]
I'll use a coordinate plane for this since it's easier (for me) :)

Red = park
Blue = his trail
Pink = distance from park = 3

Hope this helped! Please comment or DM me if you have anymore questions or don't understand :)

7 0
3 years ago
Suppose the first term of a geometric sequence is 3 and the fourth term is 192. What is the common ratio of the sequence? Write
gayaneshka [121]
An=A1 r ^(n-1)
192= 3 r ^(4-1)
192 = 3 r^3
64 = r^3
r = 4

equation:
An=3 (4)^(n-1)

6th term:
An= 3 (4)^(6-1)
An= 3072

I think this is right :)
3 0
3 years ago
What multiplication sentences are in the same fact family as 54•6 = 9
blsea [12.9K]
6•54 u just have to switch it around
3 0
4 years ago
I need help with converting liters, millilters, kiloliters etc? Okay, i am really confused! I don't understand how to get 75.01
Mamont248 [21]
Firstly, understand prefixes :)

giga 1000000000
mega 1000000
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6 0
3 years ago
In a figure, OB is the radius of a big semicircle and XB is the radius of the small semicircle. Given that OX = 14 cm, Calculate
oee [108]

Answer:

perimeter of the shaded region = 88 +44+28 =160 cm

Step-by-step explanation:

perimeter of shaded region = length AO + arc OB + arc AB

length AO = radius of bigger circle

radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm

therefore AO = 28 cm

length of arc oB= half of circumference of smaller circle = \pi×14 = 44 cm

length of arc ab = half of circumference of bigger circle  = \pi×28 =\frac{22}{7}×28= 88

therefore perimeter of the shaded region = 88 +44+28 =160 cm

area of the shaded region = half of area of bigger circle - half of area of smaller circle

                                           =\frac{1}{2} \pi 28^{2} -\frac{1}{2} \pi 14^{2}

                                           =\frac{\pi }{2} (28^{2} -14^{2} )

  solving we gen area of shaded region = 924

7 0
3 years ago
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