Answer:
12^2 + 4x
Step-by-step explanation:
We need to solve the area of these two rectangles separately.
Equation: 4x(3x+1) --> 12x + 4
Area: 12x^2 + 4x
Hope this helps.
Answer:
and as 
Step-by-step explanation:
Given
-- Missing from the question
Required
The behavior of the function around its vertical asymptote at 
Expand the numerator
Factorize
Factor out x + 1
We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)
We are only interested in the sign of the result
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As x approaches -2 implies that:
Say x = -3
We have a negative value (-12); This will be called negative infinity
This implies that as x approaches -2, p(x) approaches negative infinity
Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)
As x leaves -2 implies that: 
Say x = -2.1
We have a negative value (-56.1); This will be called negative infinity
This implies that as x leaves -2, p(x) approaches negative infinity
So, the behavior is:
and as
X^2 -15x +54 = 0 for you can factor it easy just you need getting two numbers with sum equal -15 and product equal 54
-15= (-9)+(-6) and (-9)*(-6)= -54 in this way will get
x^2 -15x +54 = (x-6)(x-9)
hope helped
<span>Triangle PQR is a right triangle. First we have to find the length of each side of the triangle. This can be done using the points provided, along with the Pythagorean theorem, which is a^2+b^2=c^2.
PR^2 = (7- -2)^2+(3-5)^2 = 85 => PR = sqrt(85)
QR^2 = (7- -1)^2+(3-1)^2 = 68 => QR = sqrt(68)
QP^2 = (1-5)^2+(-1 - -2)^2 =17 => QP = sqrt(17)
Now that we have the sides of the triangle, we can put them into the Pythagorean theorem again to see that it works out:
(Sqrt(17))^2 + (sqrt(68))^2 = (sqrt(85))^2
17 + 68 = 85
85 = 85
Since the Pythagorean theorem works for right triangles, the triangle is indeed a right triangle.</span>
