If the point U is between points T and V, then the numerical length of TV is 29 units
<h3>How to determine the numerical length of segment TV?</h3>
From the question, we have the following lengths that can be used in our computation:
- Length TU = 18 units
- Length UV = 11 units
The above parameters and representations implies that the point U is between endpoints T and V
This also means that the length TV is longer than the other lengths TU and TV
So, we have the following length equation
TV = TU + UV
Substitute the known values in the above equation
So, we have the following equation
TV = 18 + 11
Evaluate the sum of the like terms in the above equation
So, we have the following equation
TV = 29
Hence, the numerical length of segment TV is 29 units
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<u>Possible question</u>
If tu = 18 and uv = 11 what is tv, if point u is between points t and v
5a+b = 5(6)+3 =3
10-r+5 = 10-(9)+5 =6
Answer D
use photomath and sub to pewdiepie
Answer:
Step-by-step explanation:
we know that
In a join variation, If j varies jointly with respect to g and v, the equation will be of the form 
where k is a constant
step 1
Find the value of k
we have
j=2,g=4,v=3
substitute and solve for k
The equation is equal to
step 2
Find the value of j when g=8,v=9
substitute the values in the equation and solve for j
1500000000000 in scientific notation is
1.5 * 10^12
That is because you move the decimal point 12 places to the left for it to become 1.5.
1.5 * 10^12
move the decimal point 12 places to the right and you got the original number, 1500000000000.
Hope this helps!
