emma gave 2/5 of her money and an additional $9 to olivia. she gave 4/7 of her remaining money and an additional $1 to Ava. emma
2 answers:
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Answer:
See below.
Step-by-step explanation:
So, we know that Noah's purchase can be modeled by the equation:
Part 1)
The solution to the equation will be the value of x.
In this case, x will represent the original price of the jeans.
We know that Noah has a coupon for 10% off the <em>original price of the jeans</em>.
So, 0.1x will represent how much of the original price Noah gets a a discount on.
Therefore, (x - 0.1x) represents the total cost of the jeans <em>after</em> the coupon.
So, x is our original price of the jeans.
Part 2)
To verify that 70 is <em>not</em> a solution, we can simply substitute 70 for x and check whether or not the equation is true. So:
Multiply:
Subtract:
Add:
However, we <em>can</em> verify that 60 <em>is</em> the solution by substituting. So, substitute 60 for every x:
Multiply:
Subtract:
Add:
So, 60 is indeed the solution and is the value of x.
So, this means that $60 was the original price of the jeans.
1.) The interval of the value of x is from -5 to 1, inclusive. Remember that what is asked is the absolute value, thus the sign does not matter even if you have to subtract x from 5. Thus, the maximum value would be obtained if the x is smaller, which is 1. The minimum value is obtained when x=-5.
Absolute maximum value: x = - 5
f(-5) = ║5 - 7(-5)^2║ = ║-170║=170
Absolute minimum value: x = 1
f(1) = ║5 - 7(1)^2║ = ║-2║= 2
2.) The Mean Value Theorem (MVT) applies to functions that are continuous and differentiable on the closed and open interval of a to b, respectively. Since the function is a quadratic function, MVT can be applied. Then, this means that there is a value of c which is between a and b. This could be determined using this formula according to MVT:
The differentiated form would be f'(x) = -2x. Then,
Thus, x = -1, x = -1/2, and x=0 all lie in the function 4-x^2.
Absolute maximum value: x = - 5
f(-5) = ║5 - 7(-5)^2║ = ║-170║=170
Absolute minimum value: x = 1
f(1) = ║5 - 7(1)^2║ = ║-2║= 2
2.) The Mean Value Theorem (MVT) applies to functions that are continuous and differentiable on the closed and open interval of a to b, respectively. Since the function is a quadratic function, MVT can be applied. Then, this means that there is a value of c which is between a and b. This could be determined using this formula according to MVT:
The differentiated form would be f'(x) = -2x. Then,
Thus, x = -1, x = -1/2, and x=0 all lie in the function 4-x^2.
You can use cross product to slove this equation.
