g(x) = 2x-6
f(x) = -4x +7
(g•f)(x) = g(f(x))
= 2(f(x)) - 6
= 2 ( -4x+7) -6
= -8x + 14 -6
= -8x +8
now
(g•f)(1) = -8(1) + 8= -8+8
= 0
so option a is answer
Answer:
2^12
Step-by-step explanation:
16^3 = (2^4)^3 = 2^(4x3) = 2^12
Hope this helps!
The rewritten form of the expression as a single logarithm is; log {(x+3)²(x-2)^5}/(x-7)³(x²).
<h3>What is the rewritten form of the expression?</h3>
The expression given in the task content can be rewritten as a single logarithm by virtue of the laws of logarithms as follows;
2log(x+3)-3log(x-7)+5log(x-2)-log(x^2)
= log(x+3)² - log(x-7)³ +log(x-2)^5-log(x^2)
= log {(x+3)²(x-2)^5}/(x-7)³(x²)
Read more on logarithm;
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First you want to subtract 36
so it looks like this ![\sqrt[4] {(4x+164)^3}=64](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7B%284x%2B164%29%5E3%7D%3D64)
Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)
which is equal to 
Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]
Then you end up with the equation 4x+164=256
Then subtract 164 to both sides
4x=92
then divide 92 by 4
Then you get x=23
