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3 years ago

Help please thank you and also show the work please

Mathematics

1 answer:

ziro4ka [17]3 years ago

3 0

Answer:

y= -1.4x-6.6

Step-by-step explanation:

(1,-8)

7x+5y=-7

Make the equation into standard form

Subtract 7x from both sides

5y=-7x-7

Divide all by 5

y=-1.4x-1.4

Since they are parrallel, we know the slope is -1.4x

y=-1.4x+b

(1,-8) is one of the points it goes through

Replace the x and y in the equation for the x and y in the incomplete equation

-8=-1.4+b

Add 1.4 to both sides

-6.6=b

Thus the equation is

y=-1.4x-6.6

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iren2701 [21]

Answer:

V=128

Step-by-step explanation:

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3 years ago

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Given f(x) = 2x+1 and g(x) = 7/4x + 1 what is the value of f(1)-g(-4) A) -3 B) 3 C) 9 D) -9

s2008m [1.1K]

Answer:

c)9

Step-by-step explanation:

f(x)=2x+1

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<h3>Note:if you need to ask any question please let me know.</h3>

5 0

3 years ago

Inequalities <img src="https://tex.z-dn.net/?f=%20-%205%20%5Ctimes%20%20%2B%202%20%5Cgeqslant%20%20-%2048" id="TexFormula1"

Andrej [43]

$\bf -5x+2\geqslant -48\implies -5x \geqslant -50\implies \stackrel{\textit{now, we're dividing by -5}}{\cfrac{-5x}{-5}\stackrel{\stackrel{\downarrow }{\frac{}{}}}{\leqslant}\cfrac{-50}{-5}}\implies x\leqslant 10$

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3 years ago

Which phrase matches the algebraic expression below 3(x+7)+10

Vladimir79 [104]

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3 years ago

In an all boys school, the heights of the student body are normally distributed with a mean of 69 inches and a standard deviatio

slega [8]

Answer:

Two intervals are 63 and 75

Step-by-step explanation:

Given:

Mean of students (μ) = 69 inches

Standard deviation (σ) = 3 inches μ

Find:

Interval of heights (95%) using empirical rule

Computation:

Interval of heights (95%) using empirical rule:

⇒ μ – 2σ = 69 - 2(3)

⇒ μ – 2σ = 69 - 6

⇒ μ – 2σ = 63

⇒ μ + 2σ = 69 + 2 (3)

⇒ μ + 2σ = 69 + 6

⇒ μ + 2σ = 75

Two intervals are 63 and 75

7 0

3 years ago