The cost of one concert ticket is approximately $148.59.
The tickets sales for the local sales is totalled $101, 244 yesterday.
ticket sales yesterday = $101244
He sold 968 tickets with a two-days total of $143, 836 (both yesterday and today)
The cost of one ticket can be calculated below:
cost of one ticket = 143,836 / 968
cost of one ticket = 148.590909091
cost of one ticket ≈ $ 148.59
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The price of the house would need to increase by 19.05% in order to become its original price of $250,000. The price would become $250,005, which the least amount I have gotten to while attempting your question.
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Answer:

Step-by-step explanation:
Evaluate 7p + 6(p ÷ q)^2 - 2q (if p = 6 and q = 3)

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90% confidence, it can be said that the population proportion of adults who believe in UFOs is between the endpoints of the giver confidence interval [ 0.3026, 0.3348 ].
Here, we have given:
Number of adults (n) = 2272
Number of adults who believe in UFO (x) = 724
Sample proportion (p) = x/n
p = 724 / 2272
p = 0.3187
now, let q = 1 - p
q = 1 - 0.3187
q = 0.6813
Confidence level → 90%
The 90% confidence interval for population proportion is
![[ p - 1.645\frac{\sqrt{pq} }{\sqrt{n}} ,p + 1.645\frac{\sqrt{pq} }{\sqrt{n}} ]](https://tex.z-dn.net/?f=%5B%20p%20-%201.645%5Cfrac%7B%5Csqrt%7Bpq%7D%20%7D%7B%5Csqrt%7Bn%7D%7D%20%2Cp%20%2B%201.645%5Cfrac%7B%5Csqrt%7Bpq%7D%20%7D%7B%5Csqrt%7Bn%7D%7D%20%5D)
where 1.645 is Zac value at 90% confidence level.
= 0.3187 - 0.0161 = 0.3026
= 0.3187 + 0.0161 = 0.3348
90% confidence interval for the population proportion is
[ 0.3026, 0.3348 ]
Hence, With 90% confidence, it can be said that the population proportion of adults who believe in UFOs is between the endpoints of the giver confidence interval [ 0.3026, 0.3348 ]
Learn more about " Population Proportion " from here: brainly.com/question/15087042
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Answer:
Its C
Step-by-step explanation: