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zhenek [66]
3 years ago
15

Name an inscribed angle that intercepts arc AB.

Mathematics
1 answer:
True [87]3 years ago
8 0
This is you're answer for this problem

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What is the average rate of change of the function over the interval x = 0 to x = 8?<br>​
serious [3.7K]

Answer:

The average rate of change is:

\frac{13}{161}

Step-by-step explanation:

The rational function given to us is;

f(x)=\frac{3x+4}{2x+7}

f(0)=\frac{3(0)+4}{2(0)+7}

f(0)=\frac{4}{7}

f(8)=\frac{3(8)+4}{2(8)+7}

f(0)=\frac{28}{23}=1

The average rate of change of this function from x=0 to x=8  is the slope of the secant line connecting:

(0,f(0)) and (8,f(8))

Average rate of change ==\frac{f(8)-f(0)}{8-0}

=\frac{\frac{28}{23}-\frac{4}{7} }{8}

=\frac{13}{161}

7 0
3 years ago
Look at the question
tamaranim1 [39]
Your answer is:

B. subtract 10 to both sides

Hope it helps
Have a great day :)
Let me know if it’s correct
5 0
3 years ago
Bill deposits $3,000 into an account that pays simple interest at a rate of 3% per year. How much interest will he be paid in th
Sholpan [36]

Answer:

The interest he will be paid in the first 4 years is $360

Step-by-step explanation:

The rule of the simple interest is I = Prt, where

  • P is the initial deposit
  • r is the rate in decimal
  • t is the time

∵ Bill deposits $3,000 into an account

∴ P = 3000

∵ The account pays simple interest at a rate of 3% per year

∴ r = 3% = 3 ÷ 100 = 0.03

∵ The time is 4 years

∴ t = 4

→ Substitute these values in the rule above

∵ I = 3000(0.03)(4)

∴ I = 360 dollars

∴ The interest he will be paid in the first 4 years is $360

6 0
2 years ago
What is the degree of the monomial? 3x^10
zysi [14]
The degree is 0. I don't know how to solve it I just used a website that allows you to answer things like this. <span />
8 0
3 years ago
The volume V of a solid right circular cylinder is given by V = πr2h where r is the radius of the cylinder and h is its height.
emmainna [20.7K]

Answer:

8.20in³

Step-by-step explanation:

Given V = πr²h

r is the radius = 1.5in

h is the height = 6in

thickness of wall of the cylinder dr = 0.04in

top and bottom thickness dh 0.07in+0.07in = 0.14in

To compute the volume, we will find the value of dV

dV = dV/dr • dr + dV/dh • dh

dV/dr = 2πrh

dV/dh = πr²

dV = 2πrh dr + πr² dh

Substituting the values into the formula

dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14

dV = 2π (0.36)+π(1.89)

dV = 0.72π+1.89π

dV = 2.61π

dV = 2.61(3.14)

dV = 8.1954in³

Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)

7 0
3 years ago
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