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3 years ago

PLEASE HELP you just have to help with a few

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

3 0

<h3><em>Answers:</em></h3><h2 /><h2>1/4 + 2/3 =11/12</h2><h2 /><h2>2/5-1/10= 3/10</h2><h2 /><h2>1/6+1/4=5/12</h2><h2 /><h2>5/8-1/4=3/8</h2><h2 /><h2>7/8-1/2=3/8</h2><h2 /><h2>3/10+4/5=11/10 or 1 1/10</h2><h2 /><h2>5/6-2/5=3/5</h2><h2 /><h2>5/12-1/4=1/6</h2><h2 /><h2>7/16+1/8=9/16</h2><h2 /><h2>11/16+5/8=21/16 or 1 5/16</h2><h2 /><h2>2/7+1/2=11/14</h2><h2 /><h2>4/5+3/4=31/20 or 1 11/20</h2>

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3 years ago

Read 2 more answers

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OLEGan [10]

Answer:

The number of bacon and egg sandwiches sells are 2 .

Step-by-step explanation:

Let us assume that the number of coffee cups campus club sells be x .

Let us assume that the number of muffins cups campus club sells be y .

Let us assume that the number of bacon and eggs sandwiches campus club sells be z .

As given

Campus club sold a total of 55 items .

Thus the equation becomes

x + y + z = 55

Of the club members sold 5 more muffins than cups of coffee .

Thus

Number of muffins = 5 + Number of cups of coffee

y = 5 + x

Putting the value of y in the equation x + y + z = 55 .

x + 5 + x + z = 55

2x + z = 55- 5

2x + z = 50

As given

The club members charged $1 for a cup of coffee, 3$ for a muffin , and $4 for a bacon and egg sandwich and earns $119 .

Thus the equation becomes

x + 3y + 4z = 119

Putting the value of y in the above

x + 3 × (x + 5) + 4z = 119

x + 3x + 15 + 4z = 119

4x + 4z = 119 - 15

4x + 4z = 104

Simplify the above

x + z = 26

Thus the two equations are

2x + z = 50

x + z = 26

Multiply x + z = 26 subtracted from 2x + z = 50.

2x -x + z - z = 50 - 26

x = 24

Put the value of x in x + z = 26 .

24 + z =26

z = 26 - 24

z = 2

Therefore the number of bacon and egg sandwiches sells are 2 .

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