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zysi [14]
3 years ago
5

14. 2057 Q.No. 1(a) Sum to infinity:1 + 3x + 5x2 + 7x3 +... (-1<x<1).​

Mathematics
1 answer:
aleksandrvk [35]3 years ago
5 0

The sum appears to be

\displaystyle\sum_{n=0}^\infty(2n+1)x^n

I'll assume you want to find out what function this sum converges to.

Let

f(x)=\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n

with -1 < <em>x</em> < 1. Differentiating gives

f'(x)=\dfrac1{(1-x)^2}=\displaystyle\sum_{n=0}^\infty nx^{n-1}=\sum_{n=1}^\infty nx^{n-1}=\sum_{n=0}^\infty(n+1)x^n

So we have

\displaystyle\sum_{n=0}^\infty(2n+1)x^n=f'(x)+xf'(x)

\displaystyle\sum_{n=0}^\infty(2n+1)x^n=\frac{1+x}{(1-x)^2}

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