1 is tan 0 = -18/10 = -9/5
2 is tan 0 = 3/4
In general, an angle with a terminal side on the point (x, y) the tan of that line is the fraction y/x
Answer:
This college library would hold approximately ![6*10^{5}/tex] books.Step-by-step explanation:Having books on both sides, and each book being 25 centimeters (there is 100 cm in a meter, so 25 cm=0.25 m) deep, shelves must be around 50 cm (or 0.5 m) wide.If corridors must be 1,5 m wide, every two linear meters (perpendicular to corridors and shelves) of floor space there is 1.5 m of corridors and 0.5 m of shelves and that sequence repeats itself, i.e. there is 75% (1.5 of every 2 meters) of space occupied by corridors and 25% (0.5 of every 2 meters) occupied by shelves, that is:[tex]Floor space_{shelves}=Total floor space*proportion of shelves=3500m^{2} *0.25=875m^{2}](https://tex.z-dn.net/?f=6%2A10%5E%7B5%7D%2Ftex%5D%20books.%3C%2Fp%3E%3Cp%3EStep-by-step%20explanation%3A%3C%2Fp%3E%3Cp%3EHaving%20books%20on%20both%20sides%2C%20and%20each%20book%20being%2025%20centimeters%20%28there%20is%20100%20cm%20in%20a%20meter%2C%20so%2025%20cm%3D0.25%20m%29%20deep%2C%20shelves%20must%20be%20around%2050%20cm%20%28or%200.5%20m%29%20wide.%3C%2Fp%3E%3Cp%3EIf%20corridors%20must%20be%201%2C5%20m%20wide%2C%20every%20two%20linear%20meters%20%28perpendicular%20to%20corridors%20and%20shelves%29%20of%20floor%20space%20there%20is%201.5%20m%20of%20corridors%20and%200.5%20m%20of%20shelves%20and%20that%20sequence%20repeats%20itself%2C%20i.e.%20there%20is%2075%25%20%281.5%20of%20every%202%20meters%29%20of%20space%20occupied%20by%20corridors%20and%2025%25%20%280.5%20of%20every%202%20meters%29%20occupied%20by%20shelves%2C%20that%20is%3A%3C%2Fp%3E%3Cp%3E%5Btex%5DFloor%20space_%7Bshelves%7D%3DTotal%20floor%20space%2Aproportion%20of%20shelves%3D3500m%5E%7B2%7D%20%2A0.25%3D875m%5E%7B2%7D)
Knowing that every square meter of floor space occupied by shelves is in reality eight (because of being 8 shelves high) square meters of shelve space where to put books and that the average area of a book is
![Area occupied=depth*width=0.25m*0.05m=0,0125m^{2} per book](https://tex.z-dn.net/?f=Area%20occupied%3Ddepth%2Awidth%3D0.25m%2A0.05m%3D0%2C0125m%5E%7B2%7D%20per%20book)
Having all the necessary data, we estimate how many books would this college library hold:
![Books=\frac{Shelve space}{area_{book} } =\frac{875m^{2}*8 }{0.0125\frac{m^{2} }{book} } =560000 books](https://tex.z-dn.net/?f=Books%3D%5Cfrac%7BShelve%20space%7D%7Barea_%7Bbook%7D%20%7D%20%3D%5Cfrac%7B875m%5E%7B2%7D%2A8%20%7D%7B0.0125%5Cfrac%7Bm%5E%7B2%7D%20%7D%7Bbook%7D%20%7D%20%3D560000%20books)
As it is an estimate, we round it up to the nearest hundred-thousand, i.e., approximately [tex]6*10^{5}/tex] books can be shelved on this library
Answer:
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Step-by-step explanation:
The sum of complementary angles is 90º
m∠1 + m∠2=90º
52º+m∠2=90º
m∠2=90º-52º
m∠2=38º
answer: 38º
Answer:
1. operation is addition
inverse is subtraction
to solve, subtract 7. d = -2
2. operation is subtraction
inverse is addition
To solve, add 57. t = 96
3. operation is division
inverse is multiplication
to solve, multiply 2. a = 12
4. operation is multiplication
inverse is division
to solve, divide -3. x = -4