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LiRa [457]
3 years ago
13

15. A rectangle has a length of 2x - 1 and a width of 3x + 7. Find the perimeter of this rectangle.

Mathematics
1 answer:
andrew11 [14]3 years ago
7 0

Answer:

10x + 12 and 6x² + 11x - 7

Step-by-step explanation:

The perimeter (P) of a rectangle is calculated as

P = 2l + 2w ( l is length and w is width )

   = 2(2x - 1) + 2(3x + 7) ← distribute parenthesis

    = 4x - 2 + 6x + 14 ← collect like terms

     = 10x + 12

--------------------------------------------------

The area (A) of a rectangle is calculated as

A = lw

   = (2x - 1)(3x + 7) ← expand using FOIL

    = 6x² + 14x - 3x - 7 ← collect like terms

    = 6x² + 11x - 7

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<h3>How does the keypad work?</h3>

Previously, cell phone keypad had a different layout than today. The numbers were related to the letters of the alphabet and the number key was pressed according to the letters that were related.

For example, if you wanted to type the letter B, you would have to press the number 2 key twice.

The relationship of numbers and letters was distributed as follows:

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  3. D, E and F.
  4. G, H and I.
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According to the above, the table would be completed as follows.

Note: This question is incomplete because there is some missing information. Here is the missing information:

1. Complete this table to show the relation from letter to number.

Learn more about keypad in: brainly.com/question/1156254

3 0
2 years ago
I have 12 ones, and I am between 20 and 30. Who am I ?
viktelen [127]

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Answer:

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Step-by-step explanation:

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4 0
3 years ago
A rectangle has a perimeter of 30 feet and an area of 50 square feet. What are the dimensions of the rectangle?
REY [17]
Perimeter (p) = 2×length (l) + 2×width (w)
p = 2l+2w
area (a) = l×w, so solve for one (I'll use l):
a = l \times w \\ l =  a \div w \\ p = 2l + 2w = 2(l + w)
since p = 30, and a = 50, substitute the "a÷w" in for l in the perimeter equation:
p = 2(l + w) = 2((a \div w) + w) \\  = 2((a \div w) + ( {w}^{2} \div w)) \\  p= 2((a +  {w}^{2}) \div w
Now plug in p and a values:
p= 2((a +  {w}^{2}) \div w) \\ 30 = 2((50 +  {w}^{2}) \div w)  \\ 30 \div 2 = (50 +  {w}^{2}) \div w \\ 15w = 50 +  {w}^{2}
15w = 50 +  {w}^{2}  \\  {w}^{2}  - 15w + 50 = 0 \\ (w - 5)(w - 10) = 0
therefore width can be either 5 or 10 (but not both), so let's plug in:
l = a÷w = 50÷5 = 10
So if w = 5, then l = 10

D) 5 feet, and 10 feet
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3 years ago
Which statement is true about the product of a non-zero rational number and an irrational number?
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